When n = 1, 2(1) + 1 = 3
When n = 2, 2(2) + 1 = 5
When n = 3, 2(3) + 1 = 7
When n = 4, 2(4) + 1 = 9
When n = 5, 2(5) + 1 = 11
Sum = 3 + 5 + 7 + 9 + 11 = 35
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Answer: 35
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Answer:
41/6
Step-by-step explanation:
-12+81=-1+6(2a-2)
first distribute:
-12+81=-1+12a-12
combine like terms:
<u>-12+81</u>= <u>-1</u>+12a<u>-12</u>
69=-13+12a
add -13 with 69:
82=12a
divide 82 and 12:
82/12= 41/6
Answer: True
Step-by-step explanation:
Substitute 12 for x in the inequality
x > 5
12 > 5
12 is greater than 5 so x = 12 is a solution to x > 5
Answer:
A.
Step-by-step explanation:
you have to find the discriminant
b²-4ac for each equation
if discriminant < 0 no real solutions because will be negative under the squareroot whhan you try to find the roots
if discriminant = 0 there is only one solution
if discriminant > 0 two real solutions
for your given problems
A. discriminant =(-2)²-4*2*15 will be negative
Answer:
19:
4 < third side < 14
20:
3 < third side < 13
Step-by-step explanation:
hint: go to http://www.17 28.org/trianinq.htm
(fix the space between 17 and 28)
you're welcome xx
