![\begin{gathered} T=\text{ 2}\pi\sqrt[\placeholder{⬚}]{\frac{L}{9.8}} \\ 4.5=\text{ 2}\pi\sqrt[\placeholder{⬚}]{\frac{L}{9.8}} \\ \frac{4.5}{2\pi}=\text{ }\sqrt[]{\frac{L}{9.8}} \\ 0.7162=\text{ }\sqrt[]{\frac{L}{9.8}} \\ (0.7162)^2=\frac{L}{9.8} \\ 0.513(9.8)=L \\ 5.027=L \\ L\approx5.0m \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20T%3D%5Ctext%7B%202%7D%5Cpi%5Csqrt%5B%5Cplaceholder%7B%E2%AC%9A%7D%5D%7B%5Cfrac%7BL%7D%7B9.8%7D%7D%20%5C%5C%204.5%3D%5Ctext%7B%202%7D%5Cpi%5Csqrt%5B%5Cplaceholder%7B%E2%AC%9A%7D%5D%7B%5Cfrac%7BL%7D%7B9.8%7D%7D%20%5C%5C%20%5Cfrac%7B4.5%7D%7B2%5Cpi%7D%3D%5Ctext%7B%20%7D%5Csqrt%5B%5D%7B%5Cfrac%7BL%7D%7B9.8%7D%7D%20%5C%5C%200.7162%3D%5Ctext%7B%20%7D%5Csqrt%5B%5D%7B%5Cfrac%7BL%7D%7B9.8%7D%7D%20%5C%5C%20%280.7162%29%5E2%3D%5Cfrac%7BL%7D%7B9.8%7D%20%5C%5C%200.513%289.8%29%3DL%20%5C%5C%205.027%3DL%20%5C%5C%20L%5Capprox5.0m%20%5Cend%7Bgathered%7D)
Approximately 5 meters long.
Answer:
V=(4/3)πr^3
Step-by-step explanation:
This is the equation to find the volume of a sphere
V=(4/3)πr^3
than plug in 6 for x, and solve
<span>We have a right angled triangle with an opposite of 300.5 ft. (306 - 5.5) and an adjacent of 400 ft. Recalling SOH CAH TOA, tanθ = O/A.
tan(θ) = 300.5/400.
θ = tan^-1(300.5/400).
θ = 36.9°.</span>
Answer:
12
Step-by-step explanation:
PEMDAS
5+2*5-3
2*5=10
10+5=15
15-3=12
