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arsen [322]
2 years ago
8

What percent of the animals in the image are dogs?

Mathematics
2 answers:
Klio2033 [76]2 years ago
5 0
Math:

7 dogs, 3 cats, 5 birds. In total, there are 15 animals all together.

So ignore the 3 and 5 those are in there to throw you off. To get the percentage, you do 7/15

So you'd get 0.4666667

Answer: 0.467
Rounded Answer: 0.47 (Or 47% B)

VLD [36.1K]2 years ago
3 0

Answer:

Answer: 0.467

Rounded Answer: 0.47 (Or 47% B)


Step-by-step explanation:


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Use the following graph to estimate the rate of change of the function at x=0.6 using the points (0,0) and (1,−0.5)
svetoff [14.1K]

Answer:

The rate of change of the function at x = 0.6 is approximately -0.72

Step-by-step explanation:

The given information from the graph are;

Points (0, 0) and (1, -0.5)

We have that the graph is that of a cubic function, therefore;

f(x) = ax³ + bx² + cx + d

At f'(x) at  (0, 0) and (1, -0.5) = 0 gives;

3ax² + 2bx + c = 0

∴ c = 0

Also

ax³ + bx² + cx + d = 0

d = 0

We have

3a(1)² + 2b(1) + 0 = 0

3·a + 2·b = 0..............(1)

a(1)³ + b(1)² + c(1) + d = -0.5

a + b + 0×(1) + 0 = -0.5

a + b = -0.5..........(2)

Multiplying equation (2) by 2 and subtracting it from equation (1) gives;

2 × (a + b = -0.5) = 2·a + 2·b = -1

3·a + 2·b - (2·a + 2·b) = 0 - (-1) = 0 + 1 = 1

a = 1

From

a + b = -0.5, we have;

1 + b = -0.5 = 0

b = -0.5 - 1 = -1.5

The equation becomes

f(x) = x³ - 1.5·x²

The rate of change of the function at x = 0.6 is therefore given as follows;

f'(x) = 3 × x² - 2 × (1.5)·x = 3·x² - 3·x

At x = 0.6, we have;

f'(0.6) = 3·(0.6)² - 3·(0.6)

f'(0.6) = 3×0.6² - 3×0.6 = -0.72

The rate of change of the function at x = 0.6 ≈ -0.72

4 0
3 years ago
One end of a line segment has the coordinates (-6,2). If
CaHeK987 [17]

Answer:

The coordinates of the other end is (16,2)

Step-by-step explanation:

Given

End 1: (-6,2)

Midpoint: (5,2)

Required

Find the coordinates of the other end

Let Midpoint be represented by (x,y);

(x,y) = (5,2) is calculated as thus

(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})

So

x = \frac{x_1 + x_2}{2} and y = \frac{y_1 + y_2}{2}

Where (x_1,y_1) = (-6,2) and (x,y) = (5,2)

So, we're solving for (x_2,y_2)

Solving for x_2

x = \frac{x_1 + x_2}{2}

Substitute 5 for x and -6 for x₁

5 = \frac{-6 + x_2}{2}

Multiply both sides by 2

2 * 5 = \frac{-6 + x_2}{2} * 2

10 = -6 + x_2

Add 6 to both sides

6 + 10 = -6 +6 +  x_2

x_2 = 16

Solving for y_2

y = \frac{y_1 + y_2}{2}

Substitute 2 for y and 2 for y₁

2 = \frac{2 + y_2}{2}

Multiply both sides by 2

2 * 2 = \frac{2 + y_2}{2} * 2

4 = 2 + y_2

Subtract 2 from both sides

4 - 2 = 2 - 2 + y_2

y_2 = 2

(x_2,y_2) = (16,2)

Hence, the coordinates of the other end is (16,2)

3 0
2 years ago
Solve pls brainliest
Goshia [24]

Hey there!

39 = - u / 6

MULTIPLY 6 to BOTH SIDES

39(9) = (-u / 6)(6)

CANCEL out: the RIGHT side

KEEP: the LEFT side because it helps solve for the u-value

NEW EQUATION: -u = 234

DIVIDE -1 to BOTH SIDES

-1u / -1 = 234 / -1

CANCEL out: -1 / -1 because it gives you 1

KEEP: 234 / -1 because it gives you the result of the u-value

NEW EQUATION: u = 234 / -1

SIMPLIFY IT!

u = -234

Therefore, your answer is: [u = -234]

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

8 0
2 years ago
Read 2 more answers
What is the greatest common factor of 10 and 50
brilliants [131]
The greatest number common to 50 and 10 is 10 10 is the answer hope this helps
5 0
2 years ago
Read 2 more answers
Jasmine has taken an online boating safety course and is now completing her end-of-course exam. As she answers each question, th
dsp73

Answer:

There are 60 total questions on the course exam.

Step-by-step explanation:

Given that:

Number of questions finished by Jasmine = 12

Percentage shown on the bar = 20%

The total number of questions will be 100%, therefore, 20% of the questions are equal to 12.

Let,

x be the total number of questions on the course exam

20% of x = 12

\frac{20}{100}x=12\\0.2x=12

Dividing both sides by 0.2

\frac{0.2x}{0.2}=\frac{12}{0.2}\\x=60

Hence,

There are 60 total questions on the course exam.

8 0
2 years ago
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