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Marizza181 [45]
3 years ago
10

A rectangle has a perimeter of 54 miles and a height of 18 miles. What is the length of the base?

Mathematics
2 answers:
Lemur [1.5K]3 years ago
7 0

Answer: I believe it’s 9 miles

Step-by-step explanation:

tankabanditka [31]3 years ago
6 0

Answer:

972

Step-by-step explanation:

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Determine if the triangle with the given sides is acute, obtuse, or right. 36, 49, 60
kotykmax [81]
<span>When given 3 triangle sides, to determine if the triangle is acute, right or obtuse:
</span>1) Square all 3 sides.
2) Sum the squares of the 2 shortest sides.
3) Compare this sum to the square of the 3rd side.

if sum > 3rd side²   Acute Triangle
if sum = 3rd side²   Right Triangle<span>
if sum < 3rd side²   Obtuse Triangle

1) 1,296   2,401   3,600
2) Sum = 3,697
3) </span><span>3,697 is greater than 3,600
Therefore, the triangle is acute.

Source:
http://www.1728.org/triantest.htm


</span>
4 0
3 years ago
If a set xy-axes has 20 grid units in each direction and the greatest value of the data to be placed on the horizontal axis is 1
Alborosie
Use 7 scale point.
132/20 = 6.6
to its better to use more than 6.6 scale. to make it easier use 7, so to avoid decimals

 
4 0
3 years ago
Michael is using a number line to evaluate the expression –8 – 3.
djverab [1.8K]

Answer:

Micheal could rewrite the equation as negative 8 + negative 3 and move 3 spaces to the left.

Step-by-step explanation:

-8 - 3 = -8 + (-3)

5 0
3 years ago
Read 2 more answers
.Which one of the following is true when ds/dt=3t^2/2s
ser-zykov [4K]
1) Given: ds / dt = 3t^2 / 2s

2) Separate variables: 2s ds = 3t^2 dt

3) Integrate both sides:

∫ 2s ds = ∫ 3t^2 dt

s^2 + constant = t^3 + constant

=> s^2 = t^3 + constant

=> s = √ (t^3 + constant)

Answer: option B.
4 0
4 years ago
Please help me answer this question its urgent
yarga [219]

Answer:

Step-by-step explanation:

1). \frac{2}{3}n-\frac{3}{4}n+\frac{1}{6}n+2\frac{2}{9}n

= \frac{2}{3}n-\frac{3}{4}n+\frac{1}{6}n+(2+\frac{2}{9})n

= (\frac{2}{3}-\frac{3}{4}+\frac{1}{6})n+(2+\frac{2}{9})n

= (\frac{8}{12}-\frac{9}{12}+\frac{2}{12})n+(2+\frac{2}{9})n

= \frac{(8-9+2)}{12}n+(2+\frac{2}{9})n

= \frac{1}{12}n+(2+\frac{2}{9})n

= (\frac{1}{12}+2+\frac{2}{9})n

= (\frac{3}{36}+\frac{72}{36}+\frac{8}{36})n

= \frac{83}{36}n

= 2\frac{11}{36}n

2). \frac{2}{5}g-\frac{1}{6}-g+\frac{3}{10}g-\frac{4}{5}

= (\frac{2}{5}-1+\frac{3}{10})g-(\frac{1}{6}+\frac{4}{5})

= (\frac{4}{10}-\frac{10}{10}+\frac{3}{10})g-(\frac{5}{30}+ \frac{24}{30})

= (\frac{4-10+3}{10})g-(\frac{5+24}{30})

= \frac{-3}{10}g-\frac{29}{30}

= -\frac{3}{10}g-\frac{29}{30}

3). i+6i-\frac{3}{7}i+\frac{1}{3}h+\frac{1}{2}i-h+\frac{1}{4}h

= 7i-\frac{3}{7}i+\frac{1}{2}i+\frac{1}{3}h-h+\frac{1}{4}h

= (7-\frac{3}{7}+\frac{1}{2})i+(\frac{1}{3}-1+\frac{1}{4})h

= (\frac{98}{14} -\frac{6}{14}+\frac{7}{14})i+(\frac{4}{12}-\frac{12}{12}+\frac{3}{12})h

= (\frac{98-6+7}{14})i+(\frac{4-12+3}{12})h

= \frac{99}{14}i-\frac{5}{12}h

6 0
3 years ago
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