The equation of a circle with center (h,k) and radius r is
![(x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
convert it to that form by comleting the square for the x and y terms
or, we can just expand what we know
expand
![(x-a)^2+(y-b)^2=m^2](https://tex.z-dn.net/?f=%28x-a%29%5E2%2B%28y-b%29%5E2%3Dm%5E2)
and make it equal to 0
so expanding we get
![x^2-2ax+a^2+y^2-2by+b^2=m^2](https://tex.z-dn.net/?f=x%5E2-2ax%2Ba%5E2%2By%5E2-2by%2Bb%5E2%3Dm%5E2)
minus m^2 from both sides
![x^2-2ax+a^2+y^2-2by+b^2-m^2=0](https://tex.z-dn.net/?f=x%5E2-2ax%2Ba%5E2%2By%5E2-2by%2Bb%5E2-m%5E2%3D0)
arranging in decreasing power order with m² at the end
![x^2+y^2-2ax+-2by+a^2+b^2-m^2=0](https://tex.z-dn.net/?f=x%5E2%2By%5E2-2ax%2B-2by%2Ba%5E2%2Bb%5E2-m%5E2%3D0)
that is option A
answer is A
First thing we need to do is find the slope. since this equation is already in slope intercept form, which is y = mx + b, the slope is already shown. It is 1/2
The slope of the line perpendicular to the given line is the negative inverse of the slope. The negative inverse of 1/2 is -2.
Next, use the slope we determined was the negative inverse ( -2 ) and the given point ( 1,3 ) to write the equation of the line in point slope form. The formula is y − y1 = m(x − x1).
With all the correct numbers plugged in, The equation is:
y - 3 = -2 ( x - 1 )
If you would like to find the roots of the function f(x) = x^2 - 2 * x - 3, you can calculate this using the following steps:
<span>f(x) = x^2 - 2 * x - 3 = (x - 3) * (x + 1)
</span>1. x = - 1
<span>2. </span><span>x = 3
</span>
<span>The missing number would be 3.</span>
Answer:
f(2) = 1/3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 2/3x - 1
x = 2
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em>: f(2) = 2/3(2) - 1
- Multiply: f(2) = 4/3 - 1
- Subtract: f(2) = 1/3