Answer:
f(x) = 4.35 +3.95·sin(πx/12)
Step-by-step explanation:
For problems of this sort, a sine function is used that is of the form ...
f(x) = A + Bsin(2πx/P)
where A is the average or middle value of the oscillation, B is the one-sided amplitude, P is the period in the same units as x.
It is rare that a tide function has a period (P) of 24 hours, but we'll use that value since the problem statement requires it. The value of A is the middle value of the oscillation, 4.35 ft in this problem. The value of B is the amplitude, given as 8.3 ft -4.35 ft = 3.95 ft. Putting these values into the form gives ...
f(x) = 4.35 + 3.95·sin(2πx/24)
The argument of the sine function can be simplified to πx/12, as in the Answer, above.
I think the answer is c due to the word bag being plural but I’m not sure.
First rewrite it like this
1. y=5/4x
Then, make X the subject
2.4x=5/y
x=(5/y)÷4
3. Once done, simply replace x with h(x)^-1 and y with x
h(x)^-1= (5/x)÷4
Sorry I'm not very good at rearranging formula but hope this helps :)
Well, I suppose you could break up the coordinate plane
in millions of different ways.
If you take each region to be all the space that is not crossed
by an axis, then you have the four Quadrants.
1/3(12x-24)=16
*3 *3
12x-24=48
+24 +24
12x=72
/12 /12
x=6
