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prohojiy [21]
2 years ago
14

An angle measures 42.6° less than the measure of its complementary angle. What is the measure of each angle?

Mathematics
1 answer:
Setler79 [48]2 years ago
3 0

Answer:

Complementary angle 1st = 66.3°

Complementary angle 2nd = 23.7°

Step-by-step explanation:

Assume;

Complementary angle 1st = a

Complementary angle 2nd = a - 42.6°

Sum of complementary angles = 90°

So,

a + a - 42.6 = 90

a = 66.3

Complementary angle 1st = 66.3°

Complementary angle 2nd = 23.7°

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<img src="https://tex.z-dn.net/?f=0%20%3D%20%20%20-%204.9t%20%7B%7D%5E%7B2%7D%20%20%2B%2027t%20%2B%202.4" id="TexFormula1" title
marta [7]

0 =  - 4.9t {}^{2}  + 27t + 2.4
Convert decimals to fractions

0 =  -  \frac{49}{10} t {}^{2}  + 27t +  \frac{12}{5}
Multiply both sides by 10

0 =  - 49t {}^{2}  + 270t + 24
Move expression to the left.

0 + 49t {}^{2}  - 270t - 24 = 0
Remove zero.

49t {}^{2}  - 270t - 24 = 0Solve the quadratic equation.

t =  \frac{ - ( - 270) +  -  \sqrt{( - 270) {}^{2} - 4 \times 49 \times ( - 24) } }{2 \times 49}
Remove parenthesis and calculate.

t =  \frac{270 +  -  \sqrt{72900  + 4704} }{98}
Add the numbers

t =  \frac{270 +  - 77604}{98}
Separate the solutions

t =  \frac{270  +  \sqrt{77604} }{98}  \\ t =  \frac{270 -  \sqrt{77604} }{98}
The final solution are
t1 =  \frac{270 -  \sqrt{77604} }{98} , t2 =  \frac{270 +  \sqrt{77604} }{98}

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