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VMariaS [17]
3 years ago
15

In their first year, Josiah will be paid

Mathematics
2 answers:
Orlov [11]3 years ago
7 0
Read it you need to multiply 3 57
Alinara [238K]3 years ago
6 0

Answer:

their pay rate is not proportional because to be proportional the chart needs an equivalent ratio for each next layer, this one is not

Step-by-step explanation:

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There are 15 cars in Michaels toy car collection.Two thirds of the car are red.How many red cars does Michael have?
o-na [289]
The answer is 10 u have to put 2/3 multiplied by 15/1
5 0
4 years ago
Read 2 more answers
Please help me too in if sin w=-0.5 and w is a degree measure in the third quadrant, find w.
MissTica
Do you remember your unit circle? If sin ω = was -1/2, then it would be 7<span>π/6. If you're unfamiliar with the unit circle, we can derive it.

So, you know that sin is OPPOSITE/HYPOTENUSE, and it's in the third quadrant, where x and y would be negative. If sin </span>ω = -1/2, that means that ω = 1/sin*(-1/2), or sin^(-1)*(-1/2). Let's ignore the negative for now and plug sin^(-1)*(-1/2) into your calculator in radians. You get (1/6)π. But that's in Quadrant 1. We want it in Quadrant 3.

In one complete revolution, or 360°, there are 2π radians. That means, if you want to rotate it 180°, you need to add π to what you originally got.
π+(1/6)π=(7/6)π.

I highly recommend you memorize the unit circle if you haven't already, because you'll need it from Precalculus on.
6 0
3 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
!!Pleas help me!! ASAP!! I will give you BRAINLYEST!!
WARRIOR [948]

Answer:

Step-by-step explanation:

the circumference is

C=2*r*3.14=3.14*d

the below choices are the only ones that are valid

c/3.14=d

C/d=3.14

the answer B

4 0
3 years ago
Factorise fully x2 + 19x + 48​
MrMuchimi
X^2+19x+48
(x+16)(x+3)

Explanation:
Two factors of 48 that added together equal 19 are 16 and 3 so that’s why they are used
4 0
3 years ago
Read 2 more answers
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