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3 years ago

Please help me too in if sin w=-0.5 and w is a degree measure in the third quadrant, find w.

1 answer:

6 0

Do you remember your unit circle? If sin ω = was -1/2, then it would be 7<span>π/6. If you're unfamiliar with the unit circle, we can derive it.

So, you know that sin is OPPOSITE/HYPOTENUSE, and it's in the third quadrant, where x and y would be negative. If sin </span>ω = -1/2, that means that ω = 1/sin*(-1/2), or sin^(-1)*(-1/2). Let's ignore the negative for now and plug sin^(-1)*(-1/2) into your calculator in radians. You get (1/6)π. But that's in Quadrant 1. We want it in Quadrant 3.

In one complete revolution, or 360°, there are 2π radians. That means, if you want to rotate it 180°, you need to add π to what you originally got.
π+(1/6)π=(7/6)π.

I highly recommend you memorize the unit circle if you haven't already, because you'll need it from Precalculus on.

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Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th

Verizon [17]

Answer:

$(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422$

$(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778$

And we are 95% confident that the true difference means are between $1.422 \leq \mu_1 -\mu_2 \leq 2.778$

Step-by-step explanation:

We know the following info:

$\bar X_1 = 21.9$ sample mean for group 1

$\bar X_2 = 19.8$ sample mean for group 2

$s_1 = 3.4$ sample standard deviation for group 1

$s_2 = 3.5$ sample standard deviation for group 2

$n_1 = 200$ sample size group 1

$n_2 = 200$ sample size group 2

We want to find a confidence interval for the difference of means and the correct formula to do this is:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

Now we just need to find the critical value. The confidence level is 0.95 then the significance is $1-0.95 =0.05$ and $\alpha/2 =0.025$ . The degrees of freedom are given by:

$df= n_1 +n_2 -2= 200+200-2= 398$

The critical value for this case would be : $t_{\alpha/2}=1.966$

And replacing into the confidence interval formula we got:

$(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422$

$(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778$

And we are 95% confident that the true difference means are between $1.422 \leq \mu_1 -\mu_2 \leq 2.778$

5 0

3 years ago

Two doctors is what percent of 25 doctors

Anton [14]

Answer:

0. 8?

Step-by-step explanation:

you have to divide 2 by 25. If you have the percent and want to find the nonpercent like 2 of 25, then you multiply . 08 by 25 and you get 2

4 0

3 years ago

What is the equation in point-slope form if a line that passes through points (3,-5) and (-8,4)?

nignag [31]

The slope-point formula:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have (3, -5) and (-8, 4).

Substitute:

$m=\dfrac{4-(-5)}{-8-3}=\dfrac{9}{-11}=-\dfrac{9}{11}\\\\y-4=-\dfrac{9}{11}(x-(-8))\\\\y-4=-\dfrac{9}{11}(x+8)\to C)$

3 0

3 years ago

Of the following sets, which represents a function? (1 point)

yKpoI14uk [10]

Answer: Only B

============================================

Explanation:

For situation A,

x is the input and it represents the student's name.
y is the output and it represents the colors the student likes.

The pairing (x,y) tells us what a certain student likes in terms of color.

For example, the point (Allen, Red) tells us that Allen likes the color red. We could also have (Allen, Green) telling us he also likes green. Because the input "Allen" maps to more than one output, this means situation A is not a function. A function is only possible if any given input maps to exactly to one output. The input must be in the domain. The domain in this case is the set of all students in the classroom.

In contrast, Situation B is a function because a student will only have one favorite math teacher. I'm interpreting this to mean "number one favorite" and not a situation where a student can select multiple favorites.

7 0

3 years ago

Plot the points (0,1), (-1,3), (2, -3) and describe the resulting graph.

ivanzaharov [21]

check the picture below.

6 0

3 years ago