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3 years ago

What is Pi approximately equal to?

Mathematics

2 answers:

Harman [31]3 years ago

8 0

Pi is equal to 180 degrees.

anygoal [31]3 years ago

5 0

here is what it is approximately equal to

3.14159265358979323846264338327950288419716939937510

58209749445923078164062862089986280348253421170679

82148086513282306647093844609550582231725359408128

48111745028410270193852110555964462294895493038196

44288109756659334461284756482337867831652712019091

45648566923460348610454326648213393607260249141273

72458700660631558817488152092096282925409171536436

78925903600113305305488204665213841469519415116094

33057270365759591953092186117381932611793105118548

07446237996274956735188575272489122793818301194912

98336733624406566430860213949463952247371907021798

60943702770539217176293176752384674818467669405132

00056812714526356082778577134275778960917363717872

14684409012249534301465495853710507922796892589235

42019956112129021960864034418159813629774771309960

51870721134999999837297804995105973173281609631859

50244594553469083026425223082533446850352619311881

71010003137838752886587533208381420617177669147303

59825349042875546873115956286388235378759375195778

18577805321712268066130019278766111959092164201989

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A race car accelerates at 2 m/s2 from 12 m/s to 18 m/s. Find distance and time

Marizza181 [45]

Answer:

Distance = 45 meters

Time = 3 seconds

Step-by-step explanation:

Here, we want to calculate distance and time

To find the time, we can use one of the Newtons law of motion

V = U + at

In this question

V = final velocity = 18 m/s

U = initial velocity = 12 m/s

a = acceleration

Thus;

18 = 12 + 2(t)

18-12 = 2t

2t = 6

t = 6/2

t = 3 seconds

Mathematically we can also find the distance using one of the equation of motion;

D = ut + 1/2 at^2

D = 12(3) + 1/2 * (2) * 3^2

D = 36 + 9

D = 45 m

6 0

3 years ago

ella [17]

Given:

Two similar rectangles.

To find:

The area of the larger rectangle.

Solution:

Let x be the other side of the larger rectangle.

Corresponding sides of similar figures are always congruent.

$\dfrac{x}{1}=\dfrac{4}{2}$

$x=2$

The other side of larger rectangle is 2 cm.

We know that, area of rectangle is

$Area=Length\times Width$

So, area of the larger rectangle is

$Area=4\times 2$

$Area=8$

Therefore, the area of the larger rectangle is 8 sq. cm.

6 0

3 years ago

Show that a sequence {sn} coverages to a limit L if and only if the sequence {sn-L} coverages to zero.

Andreyy89

Let ${s_n}_{n\in\Bbb N}$ be a sequence that converges to $L$ . This means for any $\varepsilon>0$ , there is some $N$ such that $|s_n-L|$ for all $n>N$ . From this inequality we see that $|(s_n-L)-0|$ , so it follows that $s_n-L\to0$ .

On the other hand, let ${s_n-L}$ be a sequence that converges to 0. This means $|(s_n-L)-0|$ for all large enough $n$ , and we get the simpler inequality for free, $|s_n-L|$ , so it follows that $s_n\to L$ .