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3 years ago

Help me please, kinda lost

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

8 0

Answer:

400cm^2

Step-by-step explanation:

For this question, you need to find the surface areas of both objects, then add them together.

For the cube:

56cm for the front

56cm for the back

42cm for the side

42cm for the other side

48cm for the top

48cm for the bottom

SA for the cube: 292cm^2

For the triangle, things are a little different. We do the same process that we did to find the SA of the cube, but we do not have to find the SA of the top side (because there isn't a top side) and we have to divide the total SA by 2 because it's a triangle.

For the triangle:

42cm for the front

42cm for the back

54cm for the slanted side

42cm for the other side

36cm for the bottom

SA for the triangle: (216/2)^2=108cm^2

292+108=400cm^2

the SA of the composite figure is 400cm^2

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2t + 1 + 6 + 4t = 55<br> show your work

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Combine like terms, 1+6 is 7 and 2t+4t is 6t. so 6t+7=55. get the t by itself by subtracting 7 from both sides. 6t=48, divide by 6. t=8

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In the data set below, what are the lower quartile, the median, and the upper quartile?

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Answer:

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Step-by-step explanation:

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3 years ago

The reported unemployment is 5.5% of the population. What measurement scale is used to measure unemployment? Select one: a. Nomi

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Answer:

c. Interval or ratio

Step-by-step explanation:

There exists the following measurement scales:

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So the correct answer is:

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A research team conducted a study showing that approximately 25% of all businessmen who wear ties wear them so tightly that they

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Answer:A) 0.9866

Step-by-step explanation:

Probability of at least one tie is too tight is

Probability of tight tie 25/100

Probability of not a tight tie is 1-25/100=3/4

=1-(3/4)^15=0.9866

B)0.764

C)0.013

D)0.236

Method 2

This is binomial probability.

n=15 (number of businessmen

p=.25 (probability that a businessman wears the tie so tightly

x = number of businessmen out of 15 who wears the tie so tightly

P( at least 1) = P( x >= 1) = 1-P(x=0)

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P( at least 1) = 1- 0.013363 = 0.9866

P(more than 2) = P( x > 2) = 1-P( x=0)-P(x=1)-P(x=2)

P(x=0) = 15C0 (.25)^0 (.75)^(15-0) = (0.75)^15 = 0.013363

P(x=1) = 15C1 (.25)^1 (.75)^14 = 0.066817

P(x=2) = 15C2 (.25)^2 (.75)^13 = 0.155907

1-P( x=0)-P(x=1)-P(x=2) = 1 - 0.013363 - 0.066817 - 0.155907 = 0.763912

P(x=0) = 15C0 (.25)^0 (.75)^(15-0) = (0.75)^15 = 0.013363

P( at least 13) = P(x=13)+P(x=14)+P(x=15)

P(x=13)= 15C13 (.25)^13 (.75)^2 = 0.000001

P(x=14)= 15C14 (.25)^14 (.75)^1 = 0.000000

P(x=15)= 15C15 (.25)^15 (.75)^0 = 0.000000

P(x=13)+P(x=14)+P(x=15) = .000001+.000000+.000000 = 0.000001

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