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3 years ago

Help me please, kinda lost

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

8 0

Answer:

400cm^2

Step-by-step explanation:

For this question, you need to find the surface areas of both objects, then add them together.

For the cube:

56cm for the front

56cm for the back

42cm for the side

42cm for the other side

48cm for the top

48cm for the bottom

SA for the cube: 292cm^2

For the triangle, things are a little different. We do the same process that we did to find the SA of the cube, but we do not have to find the SA of the top side (because there isn't a top side) and we have to divide the total SA by 2 because it's a triangle.

For the triangle:

42cm for the front

42cm for the back

54cm for the slanted side

42cm for the other side

36cm for the bottom

SA for the triangle: (216/2)^2=108cm^2

292+108=400cm^2

the SA of the composite figure is 400cm^2

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2 years ago

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Answer:

$\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}$

Step-by-step explanation:

Your expression is

$\sqrt [3] {-54x^{5}y^{6}}$

Here's how I would simplify it.

$\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}$

$\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}$

$\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}$

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