Answer: should be B
Step-by-step explanation:
Answer:
1. zero triangles
2. one triangle
3. two triangles
4. zero triangles
5. one triangle
Step-by-step explanation:
Here, we need to check for all pairs by substituting the value of x & y,
1) 11 + 11 = -14(-2-2)
sides are not equal.
2) -11 + 11 = -14(2 - 2)
0 = 0
sides are equal.
In Short, Your Answer would be Option 2
Hope this helps!
The probability of selecting exactly one ace is its likelihood
The probability that a five-card poker hand contains exactly one ace is 29.95%
<h3>How to determine the probability?</h3>
There are 4 aces in a standard deck of 52 cards.
The probability of selecting an ace would be:
p = 4/52
Also, there are 48 non-ace cards in the standard deck
So, the probability of selecting a non-ace after an ace has been selected is:
p = 48/51
The probability of selecting a non-ace up to the fifth selection are:
- After two cards have been selected is: 47/50.
- After three cards have been selected is: 46/49.
- After four cards have been selected is: 45/48.
The required probability is then calculated as:
P(1 Ace) = n * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Where n is the number of cards i.e. 5
So, we have:
P(1 Ace) = 5 * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Evaluate
P(1 Ace) = 0.2995
Express as percentage
P(1 Ace) = 29.95%
Hence, the probability that a five-card poker hand contains exactly one ace is 29.95%
Read more about probability at:
brainly.com/question/25870256
Answer:
the answer is 3 root 10
forgive my mistakes. hope you understand
