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Nastasia [14]
3 years ago
14

Directions: Find each square root. Round to the nearest tenth if necessary. help?​

Mathematics
2 answers:
Archy [21]3 years ago
8 0
The square root of 289 is 17
The square root of 360 is 18.97... which would be rounded to 18
The square root of -90 is 9
Alina [70]3 years ago
3 0

Answer:

17,19,9.5

Step-by-step explanation:

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Rina8888 [55]

Answer:

1 + 1 = 2

Step-by-step explanation:

4 0
2 years ago
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What is the average of 74 and 57?
Lina20 [59]

Answer:

65.5

Step-by-step explanation:

(74 + 57)divided by 2 = 65.5

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2 years ago
F(x)= 2/x-2 find (fof) (i)
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Step-by-step explanation:

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5 0
2 years ago
I need help with this problem, if anyone could help ASAP, that would be much appreciated. In the figure below, mROP = 125° Find
VARVARA [1.3K]

Answer:

mRP = 125°

mQS = 125°

mPQR = 235°

mRPQ = 305°

Step-by-step explanation:

Given that

  • mROP = 125°
  • ∠ROP is a central angle

Then:

  • measure of arc RP, mRP = mROP = 125°

Given that

  • ∠QOS and ∠ROP are vertical angles

Then:

  • mQOS = mROP = 125°
  • measure of arc QS, mQS = mROP = 125°

Given that

  • ∠QOR and ∠SOP are vertical angles

Then:

  • mQOR = mSOP

Given that

  • The addition of all central angles of a circle is 360°

Then:

mQOS + mROP + mQOR + mSOP = 360°

250° + 2mQOR = 360°

mQOR = (360°- 250°)/2

mQOR = mSOP = 55°

And (QOR and SOP are central angles):

  • measure of arc QR, mQR = mQOR = 55°
  • measure of arc SP, mSP = mSOP = 55°

Finally:

measure of arc PQR, mPQR = mQOR + mSOP + mQOS = 55° + 55° + 125° = 235°

measure of arc RPQ, mRPQ = mROP + mSOP + mQOS = 125° + 55° + 125° = 305°

6 0
3 years ago
I need help please!:D
lidiya [134]
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6 0
3 years ago
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