<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
Answer:
Step-by-step explanation:
The Side-Angle-Side method cana only be used when information given shows that an included angle which is between two sides of a ∆, as well as the two sides of the ∆ are congruent to the included side and two sides of the other ∆.
Thus, since John already knows that 
and 
, therefore, an additional information showing that the angle between 
and 
in ∆ABC is congruent to the angle between 
and 
in ∆DEF.
For John to prove that ∆ABC is congruent to ∆DEF using the Side-Angle-Side method, the additional information needed would be .
See attachment for the diagram that has been drawn with the necessary information needed for John to prove that ∆ABC is congruent to ∆DEF.
You take
7.25 (10)+5.5p=105.5
72.5+5.5p=105.5
To make the equation easier multiply the whole equation by ten like this
(72.5+5.5p=105.5)10 that equals
725+55p=1055
Then subtract 725 to both sides
725+55p=1055
-725 -725
____ _____
55p=330
Then divide by 55 on both sides and that equals 6 so 6 people bought tickets
Answer:
12
Step-by-step explanation:
the shapes are similar which means the sides are proportional, you can set up a ratio using the sides as 10/40 = 3/x
solving that gives you x =12
