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11111nata11111 [884]
3 years ago
6

Researchers studying two populations of wolves conducted a two-sample tt-test for the difference in means to investigate whether

the mean weight of the wolves in one population was different from the mean weight of the wolves in the other population. All conditions for inference were met, and the test produced a test statistic of t=2.771t=2.771 and a pp-value of 0.01.Which of the following is a correct interpretation of the p-value?A Assuming that the mean weights of wolves in the populations are equal, the probability of obtaining a test statistic that is greater than 2.771 or less than −2.771−2.771 is 0.01.B Assuming that the mean weights of wolves in the populations are equal, the probability of obtaining a test statistic that is greater than 2.771 is 0.01.C Assuming that the mean weights of wolves in the populations are different, the probability of obtaining a test statistic that is greater than 2.771 or less than −2.771−2.771 is 0.01.D Assuming that the mean weights of wolves in the populations are different, the probability of obtaining a test statistic that is greater than 2.771 is 0.01.E Assuming that the mean weights of wolves in the populations are different, the probability of obtaining a test statistic that is less than 2.771 is 0.01.
Mathematics
1 answer:
Stells [14]3 years ago
5 0

Answer:

A. Assuming that the mean weights of wolves in the populations are equal, the probability of obtaining a test statistic that is greater than 2.771 or less than −2.771 is 0.01.

Step-by-step explanation:

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s2008m [1.1K]
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3 0
2 years ago
Madame Dubois bought 20 pearl necklaces for $500. Becoming bored quickly, she sold 3/4 of them at $40 each. She sold the rest at
Serjik [45]

$725


3/4 of 20 = 15 necklaces

15 x 40 = 600


The rest:

5 x 25 = 125


125 + 600

= 725



4 0
3 years ago
Read 2 more answers
A city council consists of seven Democrats and five Republicans. If a committee of four people is selected, find the probability
Hoochie [10]

Answer:

The probability  of selecting two Democrats and two Republicans is 0.4242.

Step-by-step explanation:

The information provided is as follows:

  • A city council consists of seven Democrats and five Republicans.
  • A committee of four people is selected.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

{n\choose k}=\frac{n!}{k!\times (n-k)!}

Compute the number of ways to select four people as follows:

{12\choose 4}=\frac{12!}{4!\times (12-4)!}=495

Compute the number of ways to selected two Democrats as follows:

{7\choose 2}=\frac{7!}{2!\times (7-2)!}=21

Compute the number of ways to selected two Republicans as follows:

{5\choose 2}=\frac{5!}{2!\times (5-2)!}=10

Then the probability  of selecting two Democrats and two Republicans as follows:

P(\text{2 Democrats and 2 Republicans})=\frac{21\times 10}{495}=0.4242

Thus, the probability  of selecting two Democrats and two Republicans is 0.4242.

6 0
2 years ago
What is greater -5.06 or 5.6
sukhopar [10]
-5.06 < 5.6 \\\\ 5.6 -is \ a \ positive \ number \ so \ is \ always \ bigger \ than \ a \ negative \ one
4 0
3 years ago
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If BC = 6 and AD = 5, find DC.
Yanka [14]

Answer: DC = 4

Step-by-step explanation: Because it is going 1 subtract everytime

4 0
3 years ago
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