Answer: 10 and 11, also -11 and -10
Sqrt 100 is well known to be 10
Sqrt 121 is 11
Step-by-step explanation:
Positive Sqrt is monotone increasing
So Sqrt 105 is between sqrt 100 and sqrt 121
Second answer
Sqrt 100 is less well known to also be -10
Negative sqrt is monotone decreasing
Sqrt 121 is also -11
Sqrt 105 is also between -121 and -100
Answer: 
Step-by-step explanation:
The midline of the function is
This means that to obtain a maximum of 10, when 
reaches it's maximum, 1, 
Question ? There is no question to help
Answer:
The sum of all exterior angles of BEGC is equal to 360° ⇒ answer F only
Step-by-step explanation:
* Lets revise some facts about the quadrilateral
- Quadrilateral is a polygon of 4 sides
- The sum of measures of the interior angles of any quadrilateral is 360°
- The sum of measures of the exterior angles of any quadrilateral is 360°
* Lets solve the problem
- DEGC is a quadrilateral
∵ m∠BEG = (19x + 3)°
∵ m∠EGC = (m∠GCB + 4x)°
∵ The sum of the measures of its interior angles is 360°
∴ m∠BEG + m∠EGC + m∠GCB + m∠CBE = 360
∴ (19x + 3) + (m∠GCB + 4x) + m∠GCB + m∠CBE = 360 ⇒ add the like terms
∴ (19x + 4x) + (m∠GCB + m∠GCB) + m∠CBE + 3 = 360 ⇒ -3 from both sides
∴ 23x + 2m∠GCB + m∠CBE = 375
∵ The sum of measures of the exterior angles of any quadrilateral is 360°
∴ The statement in answer F is only true
Answer:
Step-by-step explanation:
Given the circumference of Circle K = π
circumference of Circle L = 4π
Ratio of their circumferences = Ck/Cl
Ratio of their circumferences = π/4π
Ratio of their circumferences = 1/4 = 1:4
For their radii
C = 2πr
for circle k with circumference π
π = 2πrk
1 = 2rk
rk = 1/2
for circle l with circumference 4π
4π = 2πr
4 = 2r
r = 4/2
rl = 2
ratio
rk/rl = 1/2/2
rk/rl = 1/4 = 1:4
for the areas
Area of a circle = πr²
for circle k
Ak = π(1/2)²
Ak = π(1/4)
Ak = π/4
for circle l
Al = π(2)²
Al = 4π
Ratio of their areas
Ak/Al = π/4/(4π)
Ak/Al = π/16π
Ak/Al = 1/16 = 1:16
