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2 years ago

HELP PLEASE I CAN'T SOLVE THIS

Mathematics

1 answer:

Virty [35]2 years ago

6 0

Step-by-step explanation:

y-intercept = 2

x-intercept= 2.5

Vertex= 1,4

y=mx+b

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Learning Thoery In a learning theory project, the proportion P of correct responses after n trials can be modeled by p = 0.83/(1

elena-s [515]

Answer:

a) $P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

b) $P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

c) $0.75 =\frac{0.83}{1+e^{-0.2n}}$

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

d) If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

Step-by-step explanation:

For this case we have the following expression for the proportion of correct responses after n trials:

$P(n) = \frac{0.83}{1+e^{-0.2t}}$

Part a

For this case we just need to replace the value of n=3 in order to see what we got:

$P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

So the number of correct reponses after 3 trials is approximately 0.536.

Part b

For this case we just need to replace the value of n=7 in order to see what we got:

$P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

So the number of correct responses after 7 weeks is approximately 0.666.

Part c

For this case we want to solve the following equation:

$0.75 =\frac{0.83}{1+e^{-0.2n}}$

And we can rewrite this expression like this:

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

Now we can apply natural log on both sides and we got:

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

And we can see this on the plot attached.

Part d

If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

5 0

3 years ago

Mr. Wells runs a telecommunications company. While going through the company's project records, he found that there were 8 engin

Allisa [31]

There are 12 project managers that are employed by Mr. Wells

<h3>Further explanation</h3>

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

<em>m → gradient of the line</em>

<em>( 0 , c ) → y - intercept</em>

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

$\large {\boxed{m = \frac{y_2 - y_1}{x_2 - x_1}}}$

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

$\large {\boxed{y - y_1 = m ( x - x_1 )}}$

<em>Let us tackle the problem!</em>

$\texttt{ }$

This problem is about Directly Proportional.

<em>There were 8 engineers under every team leader.</em>

$\texttt{1 Team Leader} \rightarrow \texttt{8 engineers}$

$\texttt{15 Team Leader} \rightarrow 15 \times \texttt{8 engineers} = \boxed{\texttt{120 engineers}}$

$\texttt{ }$

<em>There were 5 project managers for every 50 engineers.</em>

$\texttt{50 engineers} \rightarrow \texttt{5 project managers}$

$\texttt{120 engineers} \rightarrow (120 \div 50) \times \texttt{5 project managers} = \boxed{\texttt{12 project managers}}$

$\texttt{ }$

<h3>Learn more</h3>

Infinite Number of Solutions : brainly.com/question/5450548
System of Equations : brainly.com/question/1995493
System of Linear equations : brainly.com/question/3291576

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

7 0

3 years ago

Which statement is true about this argument? premises: if an angle measure is greater than 90°, then the angle is an obtuse angl

vazorg [7]

Answer: option d. the argument is valid by the law of detachment.

The law of detachment consists in make a conlcusion in this way:

Premise 1) a => b
Premise 2) a is true

Conclusion: Then, b is true

Note: the order of the premises 1 and 2 does not modifiy the argument.

IN this case:

Premise 1) angle > 90 => obtuse

Premise 2) angle = 102 [i.e. it is true that angle > 90]]

Conclusion: it is true that angle is obtuse

3 0

3 years ago

Read 2 more answers

Two Algebra questions^^^

guapka [62]

5 = c. infinite.
6 = I don't know. sorry!!
Hope this helps!!

4 0

3 years ago

What is 35% of 98? I need Help with this problem?

elena55 [62]

35% of 98 is 34.3

Change the percentage (35) into a decimal by dividing over 100:

35 / 100 = 0.3

Multiply the decimal and 98:

0.35 × 98 = 34.3

8 0

2 years ago

HELP PLEASE I CAN'T SOLVE THIS ​

HELP PLEASE I CAN'T SOLVE THIS