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Katyanochek1 [597]
2 years ago
15

The function g(x) = p sin x +q, where p>0, has a maximum value of 10 and a minimum value of -4. Find the value of p and of q.

Mathematics
1 answer:
tester [92]2 years ago
7 0

Answer: p=7, q=3

Step-by-step explanation:

The midline of the function is

\frac{10-4}{2}=3 \implies q=3

This means that to obtain a maximum of 10, when \sin x reaches it's maximum, 1, g(x)=p+q=10 \implies p=7

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Interval notation x=-2 or x=0
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I have a good record of guessing the right one so I would say #1.
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Umm plz help with just the first part
harkovskaia [24]

Answer:

Factored form: -2(x + 7) = 8, x = -11 (brainliest)?

Step-by-step explanation:

-2(x + 7) = 8

x + 7 = 8 / -2

x + 7 = -4

x = -4 - 7

= -11

6 0
3 years ago
3. Jose has $400 in his bank account at the beginning of the year. Each month, he deposits $45 into his account. He does not wit
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T = 45m + 400

I hope this is correct it seems like the most logical explanation.

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3 years ago
Read 2 more answers
Compute the multifactor productivity measure for each of the weeks shown for production of chocolate bars. What do the productiv
liq [111]

Answer:

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

Step-by-step explanation:

Computation for the multifactor productivity measure for each of the weeks shown for production of chocolate bars.

Using this formula

Week Multifactor productivity measure = (Output / Total Cost)

Where:

Output represent Quantity produced

Total cost represent Labor cost + Material cost + Overhead

Let plug in the formula

Week 1= 30,000/(40*12*6)+[(40*12*6)1.5]+(450*6)

Week 1 =30,000/(2,880)+(2,880*1.5)+2,700

Week 1 =30,000/(2,880+4,320+2,700)

Week 1=30,000/9,900

Week 1 =3.03

Week 2= 33,600/(40*12*7)+[(40*12*7)1.5]+(470*6)

Week 2 =33,600/(3,360)+(3,360*1.5)+2,820

Week 2=33,600/(3,360+5,040+2,820)

Week 2=33,600/11,220

Week 2 =2.99

Week 3= 32,200/(40*12*7)+[(40*12*7)1.5]+(460*6)

Week 3 =32,200/(3,360)+(3,360*1.5)+2,760

Week 3=32,200/(3,360+5,040+2,760)

Week 3=32,200/11,160

Week 3=2.9

Week 4= 35,400/(40*12*8)+[(40*12*8)1.5]+(480*6)

Week 4 =35,400/(3,840)+(3,840*1.5)+2,880

Week 4=35,400/(3,840+5,760+2,880)

Week 4=35,400/12,480

Week 4=2.83

Therefore the multifactor productivity measure for each of the weeks shown for production of chocolate bars is :

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

4 0
2 years ago
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