Answer:
Age of Anna = x years
Age of Jane i.e. Anna's sister = (x-y) years
a, What was the sum of their ages two years ago?
Solution,
Age of Anna two years ago = (x-2) years
Age of Jane two years ago = (x-y-2) years
Sum of their ages = x - 2 + x-y-2 = 2x - y -4
b. What will be the sum of their ages in 3 years?
Solution,
We have,
Present age of Anna = x years
Present age of Jane = (x-y) years
So,
Age of Anna after 3 years = (x+3) years
Age of Jane after 3 years = (x-y+3) years
Therefore,
Sum of their ages in 3 years = (x+3) +(x-y+3) = 2x - y+6
c. How old was Anna when Jane was born?
Solution,
Here,
According to question,
Jane is y years younger than Anna
So, Anna was y years when Jane was born.
[Suppose your age is 10 years and your brothers age is 14 years. You are 4 years younger than your brother. Also, his age was 4 years when you were born.]
5 + 2(2) = 5 + 4
5 + 4 = 9
The solution is 9
1.) v=(l)(w)(h)
V=(9)(9)(9)
V=(81)(9)
V=729in^3
2.) (I forget if this is the real equation to this but this would give you the same answer)
V=(l)(w)(h)
————
2
V=(8)(6)(12)
————-
2
V=576/2
V=288cm^3
Answer:
154
Step-by-step explanation:
The area of a triangle is equal to 1/2
the base times the height.
1/2 times (base) times(height)
Substitute the values of the base b=22 and height h=14 into the formula for the area of a triangle.
1/2 times 22 times 14
Cancel the common factor of 2
Multiply
11 by 14
which will give u the area 154