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Ymorist [56]
3 years ago
14

Can you divide by zero

Mathematics
2 answers:
ANTONII [103]3 years ago
3 0

Answer:

No

Step-by-step explanation:

When you divide by 0, you will get an undefined error. When you try to graph a divide by 0, you will get asymptotes.

BigorU [14]3 years ago
3 0

Answer:

no

Step-by-step explanation:

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Write an equation that can be used to find the value of x. The perimeter of rectangle: 32 Length of the other side: 4
Sati [7]

Answer:

x=12

Step-by-step explanation:

32=2(4+x)

distribute 2.  

32=8+2x

subtract 8 from both sides.  

32=8+2x

-8   -8

24=2x

divide by 2 on both sides

24/2=2x/2

12=x

6 0
3 years ago
Explain how to estimate the square root of 1659
Nata [24]

Explanation:

Find the two closest square numbers to 1659.

40*40=1600

41*41=1681

Decide much closer to either 1600 or 1681 is 1659.

If it is exactly halfway between the two numbers, the square root is 40.5.

If it is closer to 1600, the sq rt decimal is between 1 and 4.

If it is closer to 1681, the sq rt decimal is between 6 and 9.

7 0
3 years ago
The first 5 terms of a quadratic sequence are
Mashcka [7]

Step-by-step explanation:

an = 2n^2 - 3 · Anonymous. -1, 5, 15, 29, 47, ... an = 2 n^2 - 3.

8 0
3 years ago
Algoritmo que permita calcular el área de un cuadrado
dmitriy555 [2]

Answer:

espero que esto ayude

Step-by-step explanation:

length = int (input ("Ingresa una longitud"))

width = int (input ("Ingresa un ancho"))

área = largo * ancho

imprimir ("El área es" + área)

8 0
3 years ago
Let a, b, c and x elements in the group G. In each of the following solve for x in terms of a, b, and c.
alina1380 [7]

Answer:

The answer is x=a^{-1}cb^{-1}.

Step-by-step explanation:

First, it is important to recall that the group law is not commutative in general, so we cannot assume it here. In order to solve the exercise we need to remember the axioms of group, specially the existence of the inverse element, i.e., for each element g\in G there exist another element, denoted by g^{-1} such that gg^{-1}=e, where e stands for the identity element of G.

So, given the equality axb=c we make a left multiplication by a^{-1} and we obtain:

a^{-1}axb =a^{-1}c.

But, a^{-1}axb = exb = xb. Hence, xb = a^{-1}c.

Now, in the equality xb = a^{-1}c we make a right multiplication by b^{-1}, and we obtain

xbb^{-1} = a^{-1}cb^{-1}.

Recall that bb^{-1}=e and xe=x. Therefore,

x=a^{-1}cb^{-1}.

6 0
3 years ago
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