speed of current is 1.5 mi/hr
Answer:
let the rate in still water be x and rate of the current be y.
speed down the river is:
speed=distance/time
speed=14/2=7 mi/h
speed up the river is:
speed=(14)/(3.5)=4 mi/hr
thus total speed downstream and upstream will be:
x+y=7...i
x-y=4.......ii
adding the above equations i and ii we get:
2x=11
x=5.5 mi/hr
thus
y=5-5.5=1.5 mi/r
thus the speed in still waters is 5.5 mi/hr
speed of current is 1.5 mi/hr
Answer:
First, find tan A and tan B.
cosA=35 --> sin2A=1−925=1625 --> cosA=±45
cosA=45 because A is in Quadrant I
tanA=sinAcosA=(45)(53)=43.
sinB=513 --> cos2B=1−25169=144169 --> sinB=±1213.
sinB=1213 because B is in Quadrant I
tanB=sinBcosB=(513)(1312)=512
Apply the trig identity:
tan(A−B)=tanA−tanB1−tanA.tanB
tanA−tanB=43−512=1112
(1−tanA.tanB)=1−2036=1636=49
tan(A−B)=(1112)(94)=3316
kamina op bolte
✌ ✌ ✌ ✌
Answer:
its 7
Step-by-step explanation:
If you paid $14 for 600, you paid:
600 * 14 = $8,400.00
If you sold them for $15.30 a share, you made:
600 * 15.30 = $9,180
9,180 - 8,400 = $780
The return on the investment being $780
Very very safe investment and not worth it.
