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Oduvanchick [21]
3 years ago
8

Please show me step by step so I can learn to explain it to my son.

Mathematics
1 answer:
aleksklad [387]3 years ago
6 0
These are the steps:
1. Find the area of the trapezium {Whole figure).
2. FInd the area of the rectangle (unshaded).
3. Area of the shaded = Area of trapezium - Area of the rectangle.

<u>Step 1:  Find the area of the trapezium</u>:

Formula : Area of trapezium = 1/2 (a + b)h 

Area = 1/2 ( 25 + 15) (12) = 240 yd²

<u>Step </u><u>2 :</u><u> Find the area of the rectangle</u>:

Formula : Area = Length x Width

Area = 12 x 3 = 36 yd²

<u>Step 3: Find the shaded region:</u>

240 - 36 = 204 yd²

Answer: 204 yd²

You might be interested in
If EG=19 and FG=12 then EF=?
Volgvan

Answer:

EF = 31

Step-by-step explanation:

Note that in both line segments (EG & FG), they both have point G in them. This means that point G is the shared point and the mid-point. Add the two line segments together to get the full segment.

EG + FG = EF

19 + 12 = 31

31 is your answer

~

3 0
3 years ago
12x^2+20=50 what is x
LenaWriter [7]

Answer: x=1.5811389999999999 , or 1.59

Step-by-step explanation:

First, Subtract 20 from both sides.

      12x2+20−20=50−20

      12x2=30

 Then, Divide both sides by 12:

12x^2/12 = 30/12

⇒ you get : x^2 = 5/2

After, Take square root.

x= ± √ 5/2

Finally you answer is going to be =1.5811389999999999 OR, 1.59

* Hopefully this helps:) Mark me the brainliest:)

<em>∞ 234483279c20∞</em>

7 0
3 years ago
How many sequences of 0s and 1s of length 19 are there that begin with a 0, end with a 0, contain no two consecutive 0s, and con
sladkih [1.3K]

65 sequences.

Lets solve the problem,

The last term is 0.

To form the first 18 terms, we must combine the following two sequences:

0-1 and 0-1-1

Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent

So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:

2x + 3y = 18

Case 1: x=9 and y=0

Number of ways to arrange 9 identical 2-term sequences = 1

Case 2: x=6 and y=2

Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28

Case 3: x=3 and y=4

Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35

Case 4: x=0 and y=6

Number of ways to arrange 6 identical 3-term sequences = 1

Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65

Hence the number of sequences are 65.

Learn more about Sequences on:

brainly.com/question/12246947

#SPJ4

8 0
2 years ago
The right triangle on the right is a scaled copy of the right triangle on the left. Identify the scale factor. Express your answ
Sonja [21]

Answer:

1/3

Step-by-step explanation:

the one on the left is 3 times larger than the one on the right. in other words, the right triangle's dimensions times 1/3 is equal to the left triangle's dimensions.

5 0
3 years ago
I’ll mark brainliest
Mumz [18]

Answer:

B.

Step-by-step explanation:

5 0
2 years ago
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