Answer:
In Labrador dogs, black coat is dominant to chocolate, normal vision is dominant to progressive retinal atrophy (PRA), and normal hip joint is dominant to hip dysplasia. All these genes assort independently. Two dogs that are heterozygous for alleles of all three genes are crossed. Using rules of probability (not a Punnett square), what is the chance that the first pup born to these dogs will be chocolate, have normal vision, and have normal hip joints?
BbVvHh x BbVvHh= BBVVHH, BbVvHh, BbVvHh, bbvvhh
Bb= black coat dominant
Vv= Normal vision dominant
Hh= Normal hip join dominant
probability of having a first born of these dogs will be chocolate, have normal vision and have normal hip joint is 0
Explanation:
As the punette square gives 3:1 phenotype having three black coat, normal vision and normal hip joint and one chocolate, progressive retina altropy and hip dysplasia
The answer is False
Hope this help :)
The answer is; C
Plasmids are conferred through horizontal gene transfer in bacteria. The ‘male’ bacteria develops a structure called pili that then attaches to the ‘female’ bacteria. It then transfers it’s replicated plasmid to the ‘female’ bacteria in a process called conjugation. This bacteria will hence have desirable traits that are coded for by the transferred genetic material ,such as antibiotic resistance, after a process called recombination.
