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2 years ago

4x^2+16x-4=? A. 2x(2x^2+8x-2) B. 2(2x^2+8-2) C. 4x(x^2+4x-1) D. 4(x^2+4x-1)

Mathematics

1 answer:

OLga [1]2 years ago

6 0

Answer:

Step-by-step explanation:

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Alicia borrowed $15,000 to buy a car. She borrowed the money at 8% for 6 years. What is the interest rate she will pay for the l

Likurg_2 [28]

First convert the rate into a decimal.
8/100=0.08
Next put all those numbers 15,000, 0.08, and 6 into the equation A=P(1+(rt)).
This is how you do it.
A=15,000(1+(0.08*6))
A=15,000(1+0.48)
A=15,000(1.48)
A=22,200

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3 years ago

A store is having a 20% off sale on all merchandise If Mai buys one item and save $13 what was the original price of her purchas

katrin [286]

Answer:

Step-by-step explanation:

20% off...and she saves $13

so 20% of what number is 13

0.20x = 13

x = 13/0.20

x = 65 <== original price

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2 years ago

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What is 19.184 times 0.46

Anni [7]

19.184*0.46=8.82464 the answer is: 8.82464

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2 years ago

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Which of the following best describes the

ehidna [41]

$k:6x-14y=-28\ \ \ \ |subtract\ 6x\ from\ both\ sides\\\\-14y=-6x-28\ \ \ \ \ \ |divide\ both\ sides\ by\ (-14)\\\\y=\frac{-6}{-14}x-\frac{28}{-14}\\\\y=\frac{3}{7}x+2\\----------------------------\\l:3y-7x=-14\ \ \ \ \ |add\ 7x\ to\ both\ sides\\\\3y=7x-14\ \ \ \ \ \ |divide\ both\ sides\ by\ 3\\\\y=\frac{7}{3}x-\frac{14}{3}$

$Two\ lines\ are\ perpendicular\ if\ product\ of\ the\ slopes\ is\ equal\ -1.\\\\k:y=\frac{3}{7}x+2\to the\ skolpe\ m_k=\frac{3}{7}\\\\l:y=\frac{7}{3}x-\frac{14}{3}\to the\ slope\ m_l=\frac{7}{3}\\\\m_k\times m_l=\frac{3}{7}\times\frac{7}{3}=1\neq-1\\\\conclusion:the\ lines\ are\ not\ perpendicular\\\\Two\ lines\ are\ parallel\ if\ the\ slopes\ are\ equal.\\\\m_k=\frac{3}{7};\ m_l=\frac{7}{3}\to m_k\neq m_l\\\\conclusion:the\ lines\ are\ not\ parallel$

$Answer:\boxed{C-The\ lines\ intersect\ but\ are\ not\ perpendicular.}$

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2 years ago

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Use the intersect method to solve the equation x^2-1=-x^2+7

olga55 [171]

Answer:

The solutions of the equation x^2-1=-x^2+7 are (-2,3) and (2,3)

Step-by-step explanation:

Please, see the attached file.

Thanks.

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