4x^2+16x-4=? A. 2x(2x^2+8x-2) B. 2(2x^2+8-2) C. 4x(x^2+4x-1) D. 4(x^2+4x-1)

Find the volume. Round to the nearest tenth.

sergey [27]

Answer:

a

Step-by-step explanation:

volume of cuboid = 8* 8 *23

volume of cylinder = pi * 4^2 r* 23

total colume = 2628.11

3 0

3 years ago

Complete the table of values for y=6-2x Also please work out 6-2x=3

Whitepunk [10]

Answer:

Step-by-step explanation:

x=0 y=6-2*0=6

x=1 y=6-2*1=4

x=2 y=6-2*2=2

x=3 y=6-2*3=0

6-2x=3

-6 -6

-2x=-3

2x=3

:2 :2

x=3/2

x=1.5

3 0

3 years ago

At the car show Inez saw a truck wheel shaped like a circle with a radius of 3 ft. She wants to know the area of the truck wheel

Nadusha1986 [10]

Answer:

$28.27ft^2$

Step-by-step explanation:

To solve this problem, we can use the area of a circle formula:

$A=\pi r^2$

A = area

r = radius

Lets plug the values into the equation:

$A=\pi (3^2)$ Calculate $3^2$

$A=\pi (9)$ Multiply $\pi$ and 9 together

$A=28.27$

The area of the truck wheel is $28.27ft^2$

3 0

3 years ago

the volume v of a right circular cylinder of radius r and heigh h is V = pi r^2 h 1. how is dV/dt related to dr/dt if h is const

laiz [17]

In general, the volume

$V=\pi r^2h$

has total derivative

$\dfrac{\mathrm dV}{\mathrm dt}=\pi\left(2rh\dfrac{\mathrm dr}{\mathrm dt}+r^2\dfrac{\mathrm dh}{\mathrm dt}\right)$

If the cylinder's height is kept constant, then $\dfrac{\mathrm dh}{\mathrm dt}=0$ and we have

$\dfrac{\mathrm dV}{\mathrm dt}=2\pi rh\dfrac{\mathrm dt}{\mathrm dt}$

which is to say, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ are directly proportional by a factor equivalent to the lateral surface area of the cylinder ( $2\pi r h$ ).

Meanwhile, if the cylinder's radius is kept fixed, then

$\dfrac{\mathrm dV}{\mathrm dt}=\pi r^2\dfrac{\mathrm dh}{\mathrm dt}$

since $\dfrac{\mathrm dr}{\mathrm dt}=0$ . In other words, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dh}{\mathrm dt}$ are directly proportional by a factor of the surface area of the cylinder's circular face ( $\pi r^2$ ).

Finally, the general case ( $r$ and $h$ not constant), you can see from the total derivative that $\dfrac{\mathrm dV}{\mathrm dt}$ is affected by both $\dfrac{\mathrm dh}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ in combination.

8 0

3 years ago

A store sees 138 customers in 8 hours. What is the unit rate (in customers per hour)?

Iteru [2.4K]

Answer:

Step-by-step explanation:

138/8 = 17.25

7 0

3 years ago