Answer:
g'(0) = 0
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Pre-Calculus</u>
<u>Calculus</u>
- Derivatives
- Derivative Notation
- The derivative of a constant is equal to 0
- Derivative Property:
![\frac{d}{dx} [cf(x)] = c \cdot f'(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcf%28x%29%5D%20%3D%20c%20%5Ccdot%20f%27%28x%29)
- Trig Derivative:
![\frac{d}{dx} [cos(x)] = -sin(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcos%28x%29%5D%20%3D%20-sin%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
g(x) = 8 - 10cos(x)
x = 0
<u>Step 2: Differentiate</u>
- Differentiate [Trig]: g'(x) = 0 - 10[-sin(x)]
- Simplify Derivative: g'(x) = 10sin(x)
<u>Step 3: Evaluate</u>
- Substitute in <em>x</em>: g'(0) = 10sin(0)
- Evaluate Trig: g'(0) = 10(0)
- Multiply: g'(0) = 0
Answer:
becuz their colour is black and white. b and w is so cute
Answer:
exactly what it says
Step-by-step explanation:
you see the numbers on f and g??
(F x G)x(-1)
Answer:
Step-by-step explanation:
3/5, 12/20
Answer:
22m
Step-by-step explanation:
Let height of flagpole=h
AB==17 m
(1 degree= 60 minute)

We have to find the approximate height of the flagpole.
In triangle CDA,


In triangle CDB,



Substitute the value




Substitute the value

Hence, the height of the flagpole=22 m