Value of the derivative of g(x)=8-10Cosx at 'x=0' is?

Mathematics

1 answer:

VLD [36.1K]3 years ago

3 0

Answer:

g'(0) = 0

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Pre-Calculus

Unit Circle

Calculus

Derivatives
Derivative Notation
The derivative of a constant is equal to 0
Derivative Property: $\frac{d}{dx} [cf(x)] = c \cdot f'(x)$
Trig Derivative: $\frac{d}{dx} [cos(x)] = -sin(x)$

Step-by-step explanation:

Step 1: Define

g(x) = 8 - 10cos(x)

x = 0

Step 2: Differentiate

Differentiate [Trig]: g'(x) = 0 - 10[-sin(x)]
Simplify Derivative: g'(x) = 10sin(x)

Step 3: Evaluate

Substitute in x: g'(0) = 10sin(0)
Evaluate Trig: g'(0) = 10(0)
Multiply: g'(0) = 0

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