Value of the derivative of g(x)=8-10Cosx at 'x=0' is?
1 answer:
Answer:
g'(0) = 0
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction
<u>Algebra I</u>
<u>Pre-Calculus</u>
<u>Calculus</u>
Derivatives Derivative Notation The derivative of a constant is equal to 0 Derivative Property: Trig Derivative: Step-by-step explanation:
<u>Step 1: Define</u>
g(x) = 8 - 10cos(x)
x = 0
<u>Step 2: Differentiate</u>
Differentiate [Trig]: g'(x) = 0 - 10[-sin(x)] Simplify Derivative: g'(x) = 10sin(x)
<u>Step 3: Evaluate</u>
Substitute in <em>x</em>: g'(0) = 10sin(0) Evaluate Trig: g'(0) = 10(0) Multiply: g'(0) = 0
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the ratio would be as follows
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this could also be written as a fraction 40/16 = 5/2
Answer:
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Step-by-step explanation:
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Franck's answer is better (using ~), but I just wanted to point out that the conditional in yours is slightly redundant. It's easy to forget that, since you already have a boolean value, you don't need to perform a comparison in your conditional. So you could have just done this...
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Answer:
The first graph
Step-by-step explanation:
when x is equal to something it is always up
y = 2 would be #4