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kobusy [5.1K]
3 years ago
12

Choose the function that correctly identifies the transformation of f(x) = x2 shifted two units to the left and one unit down.

Mathematics
2 answers:
AnnZ [28]3 years ago
7 0

Answer:

D) g(x) = (x + 2)^2 - 1



Pachacha [2.7K]3 years ago
4 0

Answer:

D) g(x) = (x + 2)^2 - 1

Step-by-step explanation:

Here g(x) = x^2 is a quadratic function.

The vertex form is f(x) = a(x - h)^2 + k, where "h" represents the horizontal shift and "k" represents the vertical shift.

Here h = -2 and k = -1

Plugging the values, we get

g(x) = (x - (-2))^2 - 1

g(x) = (x + 2)^2 - 1

So the answer is D) g(x) = (x + 2)^2 - 1

Hope this will helpful.

Thank you.

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Help me pleaseeeeeee
Vikki [24]
I think they are equivalent (A) but u should get a second opinion.
3 0
2 years ago
For the graph x = 1 find the slope of a line that is perpendicular to it and the slope of a line parallel to it. Explain your an
scoray [572]
Lines that are perpendicular to another line has an opposite reciprocal slope. (opposite meaning to negate the number).
Lines that are parallel have the same slope.

But the line you provided is a vertical line, and vertical lines are undefined. There is no possible perpendicular or parallel line. Maybe you gave the wrong equation and didn't put it in <em>y=mx+b</em> form. If so, you can correct it in the comments, and if not, that's you answer!

:)
5 0
3 years ago
Write the first five digits of 1/7 in base 9 expression
kaheart [24]

Compare 1/7 to consecutive multiples of 1/9. This is easily done by converting the fractions to a common denominator of LCM(7, 9) = 63:

1/9 = 7/63

2/9 = 14/63

while

1/7 = 9/63

Then 1/7 falls between 1/9 and 2/9, so 1/7 = 1/9 plus some remainder. In particular,

1/7 = 1/9¹ + 2/63.

We do the same sort of comparison with the remainder 2/63 and multiples of 1/9² = 1/81. We have LCM(63, 9²) = 567, and

1/9² = 7/567

2/9² = 14/567

3/9² = 21/567

while

2/63 = 18/567

Then

2/63 = 2/9² + 4/567

so

1/7 = 1/9¹ + 2/9² + 4/567

Compare 4/567 with multiples of 1/9³ = 1/729. LCM(567, 9³) = 5103, and

1/9³ = 7/5103

2/9³ = 14/5103

3/9³ = 21/5103

4/9³ = 28/5103

5/9³ = 35/5103

6/9³ = 42/5103

while

4/567 = 36/5103

so that

4/567 = 5/9³ + 1/5103

and so

1/7 = 1/9¹ + 2/9² + 5/9³ + 1/5103

Next, LCM(5103, 9⁴) = 45927, and

1/9⁴ = 7/45927

2/9⁴ = 14/45927

while

1/5103 = 9/45927

Then

1/5103 = 1/9⁴ + 2/45927

so

1/7 = 1/9¹ + 2/9² + 5/9³ + 1/9⁴ + 2/45927

One last time: LCM(45927, 9⁵) = 413343, and

1/9⁵ = 7/413343

2/9⁵ = 14/413343

3/9⁵ = 21/413343

while

2/45927 = 18/413343

Then

2/45927 = 2/9⁵ + remainder

so

1/7 = 1/9¹ + 2/9² + 5/9³ + 1/9⁴ + 2/9⁵ + remainder

Then the base 9 expansion of 1/7 is

0.12512..._9

8 0
2 years ago
How much longer is a 12cm pencil than a 1 dm pen
Alexxx [7]
Well one dm= 10 cm
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6 0
3 years ago
Please help me understand and answer this !!!!!!!!!!!!!!!!!
-Dominant- [34]

Answer:

5 + 8 = 13

-6 + -4 = -10

No explaination needed This answer is 1000% correct. Trust me i woould never mess someone up for no reason, not even for my own benefit.

4 0
3 years ago
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