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galina1969 [7]
3 years ago
6

-6n+4= -5 solve for n

Mathematics
1 answer:
ElenaW [278]3 years ago
5 0

Answer:

Answer is below

Step-by-step explanation:

Subtract 4 from both sides.

-6n+4(-4)=-5(-4)\\-6n=-9\\

Divide both sides by -6.

\frac{-6n}{-6}=\frac{-9}{-6}  \\n=\frac{3}{2} Decimal 1.5

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Graph the system of equations. Then determine whether the system has no solution, one solution, or infinitely many solutions. If
pav-90 [236]

Answer:

Second option: One solution. Independent.

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

Since the equations of the system have this form, we know that they are lines.

We can identify that the y-intercept of the first equation y=-5x+1 is:

b=1

Now we need to find the x-intercept. Substitute y=0 and solve for "x":

0=-5x+1\\\\5x=1\\\\x=\frac{1}{5}=0.2

Then, we can graph the first line which passess through the points (0,1) and (0.2,0). Observe the graph attached.

The y-intercept of the second equation y=-2x-2 is:

b=-2

Now we need to find the x-intercept. Substitute y=0 and solve for "x":

0=-2x-2\\\\2x=-2\\\\x=\frac{-2}{2}=-1

Then, we can graph the second line, which passess through the points (0,-2) and (-1,0).

You can observe in the graph that the lines intersect at the point (1,-4). Therefore, that point is the solution of the system of equations.

Since the lines intersect, then there is one solution that is true for both equations. It is independent

4 0
3 years ago
równanie zmiany prędkość autokaru poruszającego się po prostym odcinku szosy i rozpoczynającego hamowanie od szybkości 20m/s ma
Rasek [7]

Answer:

s = 22.5 m

Step-by-step explanation:

the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.

v (t) = 25 - 5 t

at t = 0 , v = 20 m/s

Let the distance is s.

s =\int v(t) dt\\\\s =\int (25 - 5t)dt\\\\s= 25 t - 2.5 t^2 \\

Let at t = t, the v = 20

So,

20 = 25 - 5 t

t = 1 s

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3 0
2 years ago
What is angle P<br> I will mark you.
ruslelena [56]
Angle P is an Acute Angle
6 0
2 years ago
What is the range of the function g(x) = 3x^2 - 6x + 3 when the domain is defined as the set of integers, x, such that 0&lt;=x&l
kakasveta [241]

Answer:

Range is  3 <= g(x) <= 27.

Step-by-step explanation:

The range  is the values of g(x) for the given domain.

When x = 0 g(x) = 3(0)^2 - 6(0) + 3 = 3.

When x = 4 g(x) = 3(4)^2 - 6(4) + 3 =  27.

6 0
3 years ago
PLEASE HELP ME!!! The sum of two numbers is 46. When 30 is subtracted from 5 times the smaller the result is 3 times the larger.
Ipatiy [6.2K]

Answer:

m = 21

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Step-by-step explanation:

the equations are:

n + m= 46

5m-30 = 3n

plz vote brainliest :)

8 0
3 years ago
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