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Mekhanik [1.2K]
4 years ago
10

If Georgina travels 355 km

Mathematics
1 answer:
BigorU [14]4 years ago
4 0
You have to divide 355 km by 7 hours and you will get the hour rate then multiple the hour rate by I.5 which it the extra hours you will travel for. After you get the answer of the amount of km in 1.5 hours add 355 to it. Thus, arriving to the solution of traveling 431.0714285714286km in 8.5 hours. You can round it to 431.1 km.
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-x/14+2>4?? I’m confused
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Answer: x<−28

Step-by-step explanation:

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7 calculators cost £81.90.<br> How much do 11 calculators cost?
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Answer:

128.7

Step-by-step explanation:

81.90 ÷ 7  = 11.7

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3 0
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I need help finding the domain and range for the graph
Taya2010 [7]

Answer:

Step-by-step explanation:

take two points to find the equation:

(0,4),(-2,0)

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7 0
4 years ago
V(t), left parenthesis, t, right parenthesis models the number of visitors in a park as a function of the outside temperature t
Kruka [31]

Answer:

The number of visitors increases at the same rate over both intervals

Step-by-step explanation:

The unit rate at which the number of visitors in the park increases over a given temperature interval is called the average rate of change, or ARCARCA, R, C.

To find the average rate of change of a function over an interval, we need to take the total change in the function value over the interval and divide it by the length of the interval.

Hint #22 / 3

We are asked to compare the rates at which the number of visitors increases over the interval between an outside temperature of 181818 degrees Celsius and 202020 degrees Celsius, and over the interval between an outside temperature of 202020 degrees Celsius and 272727 degrees Celsius. These correspond to the domain intervals [18,20][18,20]open bracket, 18, comma, 20, close bracket and [20,27][20,27]open bracket, 20, comma, 27, close bracket.

Let's calculate the average rate of change of VVV over those intervals:

ARC_{[18,20]}ARC

[18,20]

​

A, R, C, start subscript, open bracket, 18, comma, 20, close bracket, end subscript ARC_{[20,27]}ARC

[20,27]

​

A, R, C, start subscript, open bracket, 20, comma, 27, close bracket, end subscript

\begin{aligned} \dfrac{V(20)-V(18)}{20-18}&=\dfrac{18-10}{2}\\\\&=\dfrac{8}{2}\\\\&=4\end{aligned}\quad

20−18

V(20)−V(18)

​

​

 

=

2

18−10

​

=

2

8

​

=4

​

 \begin{aligned} \dfrac{V(27)-V(20)}{27-20}&=\dfrac{46-18}{7}\\\\&=\dfrac{28}{7}\\\\&=4\end{aligned}

27−20

V(27)−V(20)

​

​

 

=

7

46−18

​

=

7

28

​

=4

​

Hint #33 / 3

The average rate of change over the interval [18,20][18,20]open bracket, 18, comma, 20, close bracket is the same as the average rate of change over the interval [20,27][20,27]open bracket, 20, comma, 27, close bracket.

Therefore, the number of visitors increases at the same rate over both intervals.

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viva [34]
It is A, the Child is equally likely to choose a Red or a stripped ball.
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3 years ago
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