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3 years ago

A1(NO3)3 name, formula for cation an formula for anion

Chemistry

1 answer:

Nostrana [21]3 years ago

7 0

Answer:

Explanation:

The name of the compound is:

Al(NO₃)₃ is Aluminium nitrate

Aluminium nitrate is an ionic compound formed when Al loses 3 valence electrons to the nitrate.

Formula of cation: A cation is a positive charged specie

Al³⁺

Formula of anion: Anion is a negatively charged specie;

NO₃⁻

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How many grams are in .11 moles of Cu

kodGreya [7K]

Answer:

m= 6.9905 = 7 g

Explanation:

The formula is m= M.n

m= mass (g), M= Molar mass (g/mole), n= moles (moles)

Molar mass of Cu is 63.55

=) m= 63.55*0.11

m= 6.9905 = 7 g

5 0

3 years ago

A student combined two colorless aqueous solutions. One of the solutions contained Na2CO3 as the solute and the other contained

Kazeer [188]

Answer:

Bubbles will be formed when two solutions will be combined.

Explanation:

When the solution containing $Na_{2}CO_{3}$ and $HCl$ as a solute will be combined, the reaction will be as follows,

$Na_{2}CO_{3}(aq) + 2HCl(aq) \rightarrow 2NaCl(aq)+ H_{2}O(l)+CO_{2}(g)$

As a result of combination of the two solutions bubbles will be formed which will depict the evolution of carbon dioxide gas.

5 0

3 years ago

Which solution has a molality of 0.25m nacl?

Radda [10]

A 0.25m solution of NaCl is defined as a solution consisting of 0.25mol NaCl dissolved in 1kg water:
Which choice fits this definition: None does. I suggest that you recheck the data you have submitted - you have a mixture of moles, mass, etc and it is easy to make a mistake.
d) looks promising if it was: 1.0 mol NaCl dissolved in 4kg water.
I have overlooked C) as possible 0.25mol NaCl in 1kg water as being a little too obvious.

8 0

3 years ago

If you start with 100 grams of hydrogen-3, how many grams will you have after 24.6 years?

svet-max [94.6K]

Answer:

The mass left after 24.6 years is 25.0563 grams

Explanation:

The given parameters are;

The mass of the hydrogen-3 = 100 grams

The half life of hydrogen-3 which is also known as = 12.32 years

The formula for calculating half-life is given as follows;

$N(t) = N_0 \times \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{\frac{1}{2} }} }$

Where;

N(t) = The mass left after t years

N₀ = The initial mass of the hydrogen-3 = 100 g

t = Time duration of the decay = 24.6 years

$t_{\frac{1}{2} }$ = Half-life = 12.32 years

$N(24.6) = 100 \times \left (\dfrac{1}{2} \right )^{\dfrac{24.6}{12.32}} } = 25.0563$

The mass left after 24.6 years = 25.0563 grams.

4 0

3 years ago

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aivan3 [116]

Answer:

Explanation:

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3 years ago