Answer:
Mass = 5.56 g
Explanation:
Given data:
Mass of Cl₂ = 4.45 g
Mass of NaCl produced = ?
Solution:
Chemical equation:
2Cl₂ + 4NaOH → 3NaCl + NaClO₂ + 2H₂O
Number of moles of Cl₂:
Number of moles = mass/molar mass
Number of moles = 4.45 g/ 71 g/mol
Number of moles = 0.063 mol
Now we will compare the moles of Cl₂ with NaCl.
Cl₂ : NaCl
2 : 3
0.063 : 3/2×0.063 =0.095 mol
Mass of NaCl:
Mass = number of moles × molar mass
Mass = 0.095 mol × 58.5 g/mol
Mass = 5.56 g
It's either B or D because there would be 2 coefficients of hydrogen and one of oxygen
The answer is C. 7.30 x 10^-7
Answer:
C) 2CO + O₂ → 2CO₂
Explanation:
The equation C is correct.
2CO + O₂ → 2CO₂
This equation have four oxygen atom and two carbon atoms on both side of equation. So it is correctly balanced.
All others are incorrect:
A) CO + O₂ → CO₂
this is incorrect because there are three oxygen atoms on left while two atoms on right.
B) CO + 2O₂ → 2CO₂
this is incorrect because there are five oxygen atoms on left while four atoms on right.
D) 2CO + 2O₂ → 2CO₂
this is incorrect because there are six oxygen atoms on left while four atoms on right.
The answer is (3) 11,460 y. For this problem, you must know that the half life of C-14 is 5740 y and that nuclear decay processes are first order reactions (which means that the half life remains constant). For 25.00g to be left of a 100.0g sample, two half life must have elapsed (100*0.5*0.5=25). Each half life is 5730 y, so the total time elapsed is 5730 * 2 = 11,460 y.
