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3 years ago

Which is the product of 4^4(4^-7)(4)?

Mathematics

2 answers:

mihalych1998 [28]3 years ago

4 0

Answer:

0.0625

Step-by-step explanation:

$4^{4}$ ( $4^{-7}$ ) (4)

First lets deal with 4^4 which is 256 (4 * 4 * 4 * 4)

256 ( $4^{-7}$ ) (4 )

Then 4^-7 which is $\frac{1}{16384}$ ( this is because when 4^-7 is simplified it becomes 1/4^7 which is 1/16384.

256 ( $\frac{1}{16384}$ ) (4)

256 * $\frac{1}{16384}$ * 4= 0.0625

HOPE THIS HELPED

Degger [83]3 years ago

3 0

Answer:

1/16 or 0.0625

Step-by-step explanation:

we can take 4 outside the parentheses and we would get 4^(4-7+1)=4^(-2)= 1/(4^2)=1/16=0.0625.

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erma4kov [3.2K]

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2 years ago

if the morning temperature started at -7 celsius but warmed during the day to 24 celsius . What is the temperature change

Murrr4er [49]

Answer:

31° change

Step-by-step explanation:

If we want to find the change between two numbers, we need to imagine it like a number line.

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Let's plot -7 and 24 on this number line.

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If we want to get from -7 to 0, we increase by 7. To get from 0 to 24, we increase by 24.

So the total change is $7 + 24 = 31$ .

Hope this helped!

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3 years ago

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Mashutka [201]

Answer:

Because that angle is 30°.

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3 years ago

Walnuts for Sale. It costs $4.80 to buy 3/4 pound of chopped walnuts. How much would it cost to purchase 8.2 pounds of walnuts?

brilliants [131]

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2 years ago

Read 2 more answers

(b) dy/dx = (x - y+ 1)^2

Elanso [62]

Substitute $v(x)=x-y(x)+1$ , so that

$\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}$

Then the resulting ODE in $v(x)$ is separable, with

$1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx$

On the left, we can split into partial fractions:

$\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx$

Integrating both sides gives

$\dfrac{\ln|1-v|+\ln|1+v|}2=x+C$

$\dfrac12\ln|1-v^2|=x+C$

$1-v^2=e^{2x+C}$

$v=\pm\sqrt{1-Ce^{2x}}$

Now solve for $y(x)$ :

$x-y+1=\pm\sqrt{1-Ce^{2x}}$

$\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}$

3 0

3 years ago