Answer:
C
Step-by-step explanation:
in the quadratic equation: ax^2+bx+c,
in order to factor when a=1, then we need to find values that add to b and multiply to c.
You would use Pythagorean theorem to help u out if u have 2 sides u should be able to do it.
Primes are
2,3,5,7,11,13...
ok, so it must be multiplule of 2,7 and 11
2*7*11=154
answer is 154
If 36x^3a+45xa^2=9a() then 9a is a factor the other factor, (), is the left side divided by 9a
(36x^3a+45xa^2)/(9a)
4x^3+5xa
So the () term is (4x^3+5xa)
