2/3(x - 2) = 4x....distribute thru the parenthesis
2/3x - 4/3 = 4x...subtract 2/3x from both sides
-4/3 = 4x - 2/3x
-4/3 = 12/3x - 2/3x
-4/3 = 10/3x
-4/3 * 3/10 = x
-12/30 = x
- 2/5 = x <==
Set height to x, then length of base is x+3, Area formula says that
0.5*x*(x+3)=44, x(x+3)=88, x=8, x+3=11, which is the length you are looking for (11cm)
Answer:
1 min 45 sec
Step-by-step explanation:
First convert 14 min to seconds.
14 x 60 = 840s
Now we can use ratios to find the answer
840s : 800m
Divide both sides by 8
105s : 100m
105s is 1 minute and 45 seconds
The value of the median, lower and upper quartile
- Median = 21.5
- lower quartile = 12
- upper quartile = 29
<h3>What is the five-number summary for this data set?</h3>
The minimum value = 10
The maximum value = 38
The median is the value that is found in the center of the data when it is ordered from lowest to highest. In the event that there is no value that precisely corresponds to the center, the value will be determined by taking the average of the values that are located on each side of the middle.
10 11 12 15 19 24 27 29 33 38
Median = 21.5
The intermediate value of the data that is located to the left of the median is known as the lower quartile.
10 11 12 15 19
lower quartile = 12
The intermediate value of the data that is located to the right of the median is known as the upper quartile.
24 27 29 33 38
upper quartile = 29
In conclusion, the 5 number summary is 10, 12, 21.5, 29, 38 → A
Read more about median
brainly.com/question/28060453
#SPJ1
Solution:
<u>Note that:</u>
- Speed = Distance/Time
- Vaimiti speed = 1.1 m/s
- Jabril speed = 1.3 m/s
<u>Converting the time (minutes to seconds) for Vaimiti to reach school:</u>
- Vaimiti's time to reach school: 25 minutes = 25 x 60 seconds
- => Vaimiti's time to reach school: 1500 seconds
<u>Converting the time (minutes to seconds) for Jabril to reach school:</u>
- Jabril's time to reach school: 30 minutes = 30 x 60 seconds
- => Jabril's time to reach school: 1800 seconds
<u>Finding the distance of Vaimiti:</u>
Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>
- => 1.1 meters/second = Distance/1500
- => 1.1 x 1500 = Distance
- => 1650 meters = Distance (In meters)
<u>Finding the distance of Jabril:</u>
Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>
- 1.3 meters/second = Distance (In meters)/1800 seconds
- => 1.3 x 1800 = Distance (In meters)
- => 2340 meters = Distance (In meters)
This can lead to two possible solutions:
Possible solution #1:
<u>Finding the difference between the two distances:</u>
- 2340 meters - 1650 meters = Difference (In meters)
- => 690 meters
Possible solution #2:
The difference between the <u>distances they walked</u> is that Jabril walked <u>faster</u> than Vaimiti, but Vaimiti reached <u>school</u> earlier than Jabril because the <u>walking distance</u> for Vaimiti is less than the <u>walking</u> <u>distance</u> for Jabril.
Hoped this helped!