Answer:
Null hypothesis:
Alternative hypothesis:
And based on this the best option for this case is:
Ha: μregular > μspecial H0: μregular = μspecial
Step-by-step explanation:
For this case the interest is verify if the true average amount of warpage for that laminate is less than for the regular laminate.
Let's put notation:
represent the true mean for the amount of warpage for the regular laminate
represent the true mean for the amount of warpage for the special laminate
And based on the claim, the correct system of hypothesis are:
Null hypothesis:
Alternative hypothesis:
And based on this the best option for this case is:
Ha: μregular > μspecial H0: μregular = μspecial
Answer:
(i think it is for q6 so) $6
Step-by-step explanation:
4.50÷3=1.50 (that's for 1 pound of fudge)
1.50×4=6
Answer:
38.25 cm²
Step-by-step explanation:
We use the formula for the length of an arc to find the central angle of the sector of the circle.
Then we use the formula for the area of a sector of a circle to find the area.
Length of arc of circle of radius r:
s = arc length
n = measure of the central angle of the sector
Area of sector of circle of radius r:
A = area of sector of circle
n = measure of the central angle of the sector
Answer:
75
Step-by-step explanation:
Answer:
10ac is not equal
Step-by-step explanation:
a · c · 5 · 5
5*5 = 25
25ac
25ca