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prohojiy [21]
3 years ago
13

Y= 10x - 32 what is the x and y value of this equation

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
6 0

Answer:

It depends, Y or X have to be set up to get an actual number because you can simply plug any numbers.

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Rewrite the following quadratic functions in intercept or factored form. Show your work.
Dmitry [639]

<u>Answer: </u>

f(x) = 3(x+2)(x-2)

<u>Step-by-step explanation: </u>

We are given the following the quadratic function and we are to rewrite it in intercept or factored form:

f(x) = 3x^2 - 12

We can factorize the given function so taking the common factors out of it to get:

f(x)=3x^2 - 12

f(x) = 3 (x^2 - 4)

The term (x^2-4) is in the form a^2-b^2 so it can further be factorized to give:

f(x) = 3 (x+2)(x-2)

Therefore, the factored form of the given quadratic function is f(x) = 3(x+2)(x-2).


7 0
3 years ago
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carly and rob combined their dvd collections. now they have 42 dvds in all carly had 4 more dvds than rob. how many dvds did car
mrs_skeptik [129]
So r+c=42 c=4+r subsitute c=4+r for r in r+c=42 r+4+r=42 add like terms 2r+4=42 subtract 4 from both sides 2r=38 divide both sides by 2 r=19 rob=19 subsitute r=19 for r in c=4+r c=19+4 carly=23
5 0
3 years ago
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15% of what number is 900?
Ugo [173]

Answer:

135

Step-by-step explanation:

15/100 × 900 = 15 × 9 = 135

3 0
3 years ago
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4p+25=6(p-3)-3(4-3p)
Wewaii [24]
P = 5 .............................................
this is how= 

first you expand the second equation 
<span>25 + 4p = -18 + -12 + 6p + 9p
</span>
then you add the like terms in the second equation:
25 + 4p = -30 + 15p
then this is how=
25+30 = 15p -4p
55=11p

p= 5

3 0
3 years ago
For a study regarding mean cadence, two-way ANOVA was used. The two factors were walking device (none, standard walker, rolling
goldenfox [79]

Answer:

Step-by-step explanation:

With regards to the factor 'walking device used', the ANOVA conducted on the cadence data revealed a main effect of walking device, and also with the results of the experiment giving rise to a p - value less than 0.05, we can reject the null hypothesis which says, there is no effect of the walking device factor.

We can thus conclude that there is not enough statistics evidence to prove that there is no interaction between the two factors or that there is no effect of the walking device given the cadence data.

4 0
3 years ago
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