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Alex_Xolod [135]
3 years ago
13

1+1=? idk what is is!! PLEASE HELP NOW!!

Mathematics
2 answers:
slamgirl [31]3 years ago
8 0

Answer: 2

Step-by-step explanation:

This was a really hard one...

I recommend using your fingers to count...put one finger up as one and another one up as two!

Marrrta [24]3 years ago
6 0

Answer:

2...................

Step-by-step explanation:

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Help again...brainliest
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Answer:

A.

Step-by-step explanation:

Atom is the smallest thing g possible and organ is the biggest on that list.

8 0
3 years ago
One number is 3 less than 4 times a second number. The difference of the first number and twice the second number is 7. What are
Nikolay [14]

Answer:

atq= let no.be x and y

x= 4y-3.......(1)

x-2y=7....(2)

subtracting both eqn

x-x+2y=4y-3-7

2y=4y-10

-2y= -10

y=5 ........second no.

first no...x=7+2y=7+10=17.......first no....

5 0
3 years ago
What is the equation of the line showed in this graph?
Irina-Kira [14]

Answer:

y=1

Step-by-step explanation

3 0
3 years ago
Find the points on the ellipse 4x2 + y2 = 4 that are farthest away from the point (−1, 0).
Hitman42 [59]
<span>The two points that are most distant from (-1,0) are exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3) approximately (0.3333333, 1.885618) and (0.3333333, -1.885618) Rewriting to express Y as a function of X, we get 4x^2 + y^2 = 4 y^2 = 4 - 4x^2 y = +/- sqrt(4 - 4x^2) So that indicates that the range of values for X is -1 to 1. Also the range of values for Y is from -2 to 2. Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis. So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So y = sqrt(4-4x^2) distance is sqrt((x + 1)^2 + sqrt(4-4x^2)^2) =sqrt(x^2 + 2x + 1 + 4 - 4x^2) =sqrt(-3x^2 + 2x + 5) And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving -3x^2 + 2x + 5 Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative. d = -3x^2 + 2x + 5 d' = -6x + 2 And set d' to 0 and solve for x, so 0 = -6x + 2 -2 = -6x 1/3 = x So the furthest point will be where X = 1/3. Calculate those points using (1) above. y = +/- sqrt(4 - 4x^2) y = +/- sqrt(4 - 4(1/3)^2) y = +/- sqrt(4 - 4(1/9)) y = +/- sqrt(4 - 4/9) y = +/- sqrt(3 5/9) y = +/- sqrt(32)/sqrt(9) y = +/- 4sqrt(2)/3 y is approximately +/- 1.885618</span>
7 0
4 years ago
Which value of x makes the equation 8x + 38 = 2(11x + 5) true?
dangina [55]
8x+38=2(11x+5)
divide 2 from both sides
4x+19=11x+5
minus 4x from both sides
19=7x+5
minus 5 from both sides
14=7x
divide by 7
2=x

so x would be 2
3 0
2 years ago
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