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SVETLANKA909090 [29]
2 years ago
14

Write x2 - 8x + 13 = 0 in the form (x - a)2 = b, where a and b are integers.

Mathematics
1 answer:
Mariana [72]2 years ago
6 0

Answer:

A.  (x - 4)² = 3

Step-by-step explanation:

You need to change the equation so that you can make a square.  To get a square, you need to analyze the terms.  

x² has a a coefficient of one, so you don't have to worry about that.

13 is going to be changed so that it can be a square.  

8x is what you should be looking at.  For a square, the middle term is the number multiplied by 2.  This means that the square was (x - 4)².  

A square, when expanded, has the square of the number as the last term.  This means that your last term should be 16.  You need to add 3 to both sides of the equation to make this true.

x² - 8x + 13 = 0

x² - 8x + 13 + 3 = 0 + 3

x² - 8x + 16 = 3

(x - 4)² = 3

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Answer:

The expanded value of the given expression is

(3a^4b)(5ab^2)-(a^5b^2)(9b)=6a^5b^3

Step-by-step explanation:

Given expression is                                                                              

(3a^4b)(5ab^2)-(a^5b^2)(9b)

To find the value of the given expression:

(3a^4b)(5ab^2)-(a^5b^2)(9b)=15a^5b^3-9a^5b^3

(By multiplying the products and doing algebraci subtracion of the above expression)

Now taking the common terms in the above equation we get

(3a^4b)(5ab^2)-(a^5b^2)(9b)=3a^5b^3(5-3)

                                             =3a^5b^3(2)

                                             =6a^5b^3

Therefore the expanded value of the given expression is

(3a^4b)(5ab^2)-(a^5b^2)(9b)=6a^5b^3

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