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4 years ago

Combine the like terms to create an equivelant expression -3x-6(-1)

Mathematics

1 answer:

Elza [17]4 years ago

3 0

Answer:

-3x+6

Step-by-step explanation:

-3x-6(-1)

First, multiplying two negatives equals a positive: (-)×(-)=(+). Then,

multiply the numbers -3×+6×1 = -3x+6. Then, you got the answer and the answer is -3x+6

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What percent is represented by the shaded area?

bija089 [108]

Answer:

110%

Step-by-step explanation:

because there are two different squares that represent a whole, each with ten sections, the most reasonable answer would be 110%. I hope this helps you!

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3 years ago

What is the expanded form of (x-2)(x+2)

Stels [109]

Answer:

(x^2)-4

Step-by-step explanation:

expand using the distributive property of multiplication

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3 years ago

Read 2 more answers

How do you work out 2 over 1.5 + 2.45 on a calculator?

erik [133]

Answer:

You have to use parenthesis

Enter:

2 ÷ (1.5+2.45) =

Step-by-step explanation:

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3 years ago

In one year, a government collected $6770 per person in taxes. If the population was 220,000,000, how much did the government co

ollegr [7]

Answer:

$1,489,400,000,000

Step-by-step explanation:

Multiply to get the solution.

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3 years ago

Find the critical points of the surface f(x, y) = x3 - 6xy + y3 and determine their nature.

Vedmedyk [2.9K]

Compute the gradient of $f$ .

$\nabla f(x,y) = \left\langle 3x^2 - 6y, -6x + 3y^2\right\rangle$

Set this equal to the zero vector and solve for the critical points.

$3x^2-6y = 0 \implies x^2 = 2y$

$-6x+3y^2=0 \implies y^2 = 2x \implies y = \pm\sqrt{2x}$

$\implies x^2 = \pm2\sqrt{2x}$

$\implies x^4 = 8x$

$\implies x^4 - 8x = 0$

$\implies x (x-2) (x^2 + 2x + 4) = 0$

$\implies x = 0 \text{ or } x-2 = 0 \text{ or } x^2 + 2x + 4 = 0$

$\implies x = 0 \text{ or } x = 2 \text{ or } (x+1)^2 + 3 = 0$

The last case has no real solution, so we can ignore it.

Now,

$x=0 \implies 0^2 = 2y \implies y=0$

$x=2 \implies 2^2 = 2y \implies y=2$

so we have two critical points (0, 0) and (2, 2).

Compute the Hessian matrix (i.e. Jacobian of the gradient).

$H(x,y) = \begin{bmatrix} 6x & -6 \\ -6 & 6y \end{bmatrix}$

Check the sign of the determinant of the Hessian at each of the critical points.

$\det H(0,0) = \begin{vmatrix} 0 & -6 \\ -6 & 0 \end{vmatrix} = -36 < 0$

which indicates a saddle point at (0, 0);

$\det H(2,2) = \begin{vmatrix} 12 & -6 \\ -6 & 12 \end{vmatrix} = 108 > 0$

We also have $f_{xx}(2,2) = 12 > 0$ , which together indicate a local minimum at (2, 2).

3 0

2 years ago