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nata0808 [166]
3 years ago
7

Planes S and R both intersect plane T.

Mathematics
1 answer:
Paraphin [41]3 years ago
4 0

Answer:

The true statements are;

1) The line containing points A and B lies entirely in plane T

2) Line z intersects plane S at point C

3) Planes R and T intersect at line y

Step-by-step explanation:

1) The points A and B are located on the line v which can be found on the plane T

2) As shown on the diagram, the line z, that has points C and D, passes through the plane Z at the point C

3) The intersection of the planes R and T is the line y. This is so because, the intersection of two planes  can be seen as a line that is along the area of their intersection.

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Step-by-step explanation:

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3 years ago
Y + 2 = -2x +6<br> 3x + 9y = 6
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In △ABC, ∠ABC = 60 degrees .
ira [324]

A given<u> shape</u> that is <em>bounded</em> by three <u>sides</u> and has got three <em>internal angles</em> is referred to as a <u>triangle</u>. Thus the <em>value</em> of <u>PB</u> is 8.0 units.

A given <em>shape</em> that is <u>bounded</u> by three<em> sides</em> and has got three <em>internal angles</em> is referred to as a <u>triangl</u>e. Types of <u>triangles</u> include right angle triangle, isosceles triangle, equilateral triangle, acute angle triangle, etc. The sum of the<em> internal angles</em> of any <u>triangle</u> is 180^{o}.

In the given question, point<u> P</u> is <u>center</u> of the given <u>triangle</u> such that <APB = <APC = <BPC = 120^{o}. Such that <u>line</u> PB <em>bisects</em> <ABC into two <u>equal</u> measures of 30^{o}.

Thus;

<ABP = 30^{o}

Thus,

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Apply the <em>Sine rule</em> to determine the value of PB, such that;

\frac{a}{SinA} = \frac{b}{SinB}

\frac{8}{Sin 30} = \frac{PB}{Sin 30}

BP = \frac{8*Sin 30}{Sin 30}

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BP = 8.0

Therefore, the value of <u>PB</u> = 8 units.

For more clarifications on Sine rule, visit: brainly.com/question/27174058

#SPJ1

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2 years ago
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Answer:

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