We can then write an equation representing this problem as:
e−1.5mi=5.25mi
Now, add 1.5mi to each side of the equation to solve for e while keeping the equation balanced:
e−1.5mi+1.5mi=5.25mi+1.5mi
e−0=6.75mi
e=6.75mi
The plane's starting elevation was 6.75 miles
Hope this helps!
Answer: B
Step-by-step explanation:
LJ should corresponds with RQ but it should correspond with PR.
Answer:
The intensity of the first earthquake is 6.31 times the second one
Step-by-step explanation:
The given formulae is M=log(
)
Here for both the earthquakes the value of S is same.
Let the Intensity of the first earthquake be I1 and the second be I2.
Given M1=7.5
M2=6.7
Now M1=log(
)------1
M2=log(
)-----2
Now subtract 1 and 2 we get
M1-M2=log(
)
I1/I2=
I1=I2(
I1=I2*6.31
Answer:
see explanation
Step-by-step explanation:
Using the Addition formula for sine
sin(x ± y) = sinxcosy ± cosxsiny
Consider the left side
sin(360 - Θ ), then
= sin360°cosΘ - cos360°sinΘ
= 0 × cosΘ - 1 × sinΘ
= 0 - sinΘ = - sinΘ → verified