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3 years ago

Find the length of the given segment. Find LN

Mathematics

1 answer:

Lapatulllka [165]3 years ago

8 0

Answer:

x+10=1/2*(x+2)

2x+20=x+2

20-2= x-2x

x= -18

now,

LN= X+10

= -18+10

= -8

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What’s the correct answer

masha68 [24]

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3 years ago

Factor 64b-16c to identify the equivalent expressions. *

scoray [572]

Answer:

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Step-by-step explanation:

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3 years ago

How can I solve number 4 and 6?

SOVA2 [1]

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3 years ago

A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect

krek1111 [17]

Answer:

The probability that the first two electric toothbrushes sold are defective is 0.016.

Step-by-step explanation:

The probability of an event, say E occurring is:

$P (E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let X = number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is, n = 20.

Number of defective electric toothbrushes is, x = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

${20\choose 2}=\frac{20!}{2!(20-2)!}=\frac{20!}{2!\times 18!}=\frac{20\times 19\times 18!}{2!\times 18!}=190$

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

${3\choose 2}=\frac{3!}{2!(3-2)!}=\frac{3!}{2!\times 1!}=3$

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

$=\frac{3}{190}\\$

$=0.01579\\\approx0.016$

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

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3 years ago

kevin answered 54 out of 60 questions correct on his algebra quiz.what is his score as a percent ? round your answer to the near

Mila [183]

Answer: 90%

Step-by-step explanation:

54/60=0.9 0.9*100= 90

6 0

3 years ago

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