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bagirrra123 [75]
3 years ago
11

HELP ASAP

Mathematics
1 answer:
klasskru [66]3 years ago
8 0

Answer:

the answer is D. she loses 75

Step-by-step explanation:

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A student ran a distance of 2 1/2 miles each day for 9 days. The student ran a distance of 5 3/4 miles each day for the next 3 d
cestrela7 [59]

Answer:

39.75 miles

Step-by-step explanation:

5 0
3 years ago
The women’s world record high jump is 6 feet, 10 ¼ inches. What is the record in meters? Record your answer to the nearest hundr
valina [46]
2.08. If you want to round, then it will be 2.09.

Hope this helps! ;)
7 0
3 years ago
2. In how many ways can 3 different novels, 2 different mathematics books and 5 different chemistry books be arranged on a books
insens350 [35]

The number of ways of the books can be arranged are illustrations of permutations.

  • When the books are arranged in any order, the number of arrangements is 3628800
  • When the mathematics book must not be together, the number of arrangements is 2903040
  • When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
  • When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

\mathbf{Novels = 3}

\mathbf{Mathematics = 2}

\mathbf{Chemistry = 5}

<u />

<u>(a) The books in any order</u>

First, we calculate the total number of books

\mathbf{n = Novels + Mathematics + Chemistry}

\mathbf{n = 3 + 2 +  5}

\mathbf{n = 10}

The number of arrangement is n!:

So, we have:

\mathbf{n! = 10!}

\mathbf{n! = 3628800}

<u>(b) The mathematics book, not together</u>

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

\mathbf{Maths\ together = 2 \times 9!}

Using the complement rule, we have:

\mathbf{Maths\ not\ together = Total - Maths\ together}

This gives

\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}

\mathbf{Maths\ not\ together = 2903040}

<u>(c) The novels must be together and the chemistry books, together</u>

We have:

\mathbf{Novels = 3}

\mathbf{Chemistry = 5}

First, arrange the novels in:

\mathbf{Novels = 3!\ ways}

Next, arrange the chemistry books in:

\mathbf{Chemistry = 5!\ ways}

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

\mathbf{n =Mathematics + 1 + 1}

\mathbf{n =2 + 1 + 1}

\mathbf{n =4}

So, the number of arrangements is:

\mathbf{Arrangements = n! \times 3! \times 5!}

\mathbf{Arrangements = 4! \times 3! \times 5!}

\mathbf{Arrangements = 17280}

<u>(d) The mathematics must be together and the chemistry books, not together</u>

We have:

\mathbf{Mathematics = 2}

\mathbf{Novels = 3}

\mathbf{Chemistry = 5}

First, arrange the mathematics in:

\mathbf{Mathematics = 2!}

Literally, the number of chemistry and mathematics now is:

\mathbf{n =Chemistry + 1}

\mathbf{n =5 + 1}

\mathbf{n =6}

So, the number of arrangements of these books is:

\mathbf{Arrangements = n! \times 2!}

\mathbf{Arrangements = 6! \times 2!}

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

\mathbf{Arrangements = ^7P_3}

So, the total arrangement is:

\mathbf{Total = 6! \times 2!\times ^7P_3}

\mathbf{Total = 6! \times 2!\times 210}

\mathbf{Total = 302400}

Read more about permutations at:

brainly.com/question/1216161

8 0
2 years ago
A cuboid with a volume of 924cm^3 has dimensions 4cm, (x+1)cm and (x+11). Show clearly that x^2+12x-220=0 solve the equation by
garik1379 [7]

Answer:

x^2+12x-220=0 -- Proved

x = 10\ \ \ x = -22

Step-by-step explanation:

Given

Volume = 924cm^3

Dimension: 4cm; (x+1)cm; (x+11)cm

Required

Show that x^2+12x-220=0

The volume is calculated as:

4 * (x + 1) * (x + 11) = 924

Open the brackets

(4x + 4) * (x + 11) = 924

4x^2 + 44x + 4x + 44 = 924

4x^2 + 48x+ 44 = 924

Collect Like Terms

4x^2 + 48x+ 44 - 924=0

4x^2 + 48x -880=0

Divide through by 4

\frac{4x^2}{4} + \frac{48x}{4} -\frac{880}{4}=0

x^2+12x-220=0

Solving further:

Expand the expression

x^2 + 22x - 10x - 220 = 0

Factorize:

x(x + 22) - 10(x + 22) = 0

(x - 10)(x + 22) = 0

Split:

x - 10 = 0;\ \ \ x + 22 = 0

x = 10\ \ \ x = -22

5 0
2 years ago
HELPPPPPPP PLEASEEEEE
egoroff_w [7]

Answer:

5^15

Step-by-step explanation:

if they have the same base then you add the two top vaules therfore giving you c.

Brainliest plzzzzzzz

4 0
2 years ago
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