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bagirrra123 [75]

3 years ago

11

HELP ASAP

1 answer:

klasskru [66]3 years ago

8 0

Answer:

the answer is D. she loses 75

Step-by-step explanation:

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A student ran a distance of 2 1/2 miles each day for 9 days. The student ran a distance of 5 3/4 miles each day for the next 3 d

cestrela7 [59]

Answer:

39.75 miles

Step-by-step explanation:

5 0

3 years ago

The women’s world record high jump is 6 feet, 10 ¼ inches. What is the record in meters? Record your answer to the nearest hundr

valina [46]

2.08. If you want to round, then it will be 2.09.

Hope this helps! ;)

7 0

3 years ago

2. In how many ways can 3 different novels, 2 different mathematics books and 5 different chemistry books be arranged on a books

insens350 [35]

The number of ways of the books can be arranged are illustrations of permutations.

When the books are arranged in any order, the number of arrangements is 3628800
When the mathematics book must not be together, the number of arrangements is 2903040
When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

$\mathbf{Novels = 3}$

$\mathbf{Mathematics = 2}$

$\mathbf{Chemistry = 5}$

<u />

<u>(a) The books in any order</u>

First, we calculate the total number of books

$\mathbf{n = Novels + Mathematics + Chemistry}$

$\mathbf{n = 3 + 2 + 5}$

$\mathbf{n = 10}$

The number of arrangement is n!:

So, we have:

$\mathbf{n! = 10!}$

$\mathbf{n! = 3628800}$

<u>(b) The mathematics book, not together</u>

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

$\mathbf{Maths\ together = 2 \times 9!}$

Using the complement rule, we have:

$\mathbf{Maths\ not\ together = Total - Maths\ together}$

This gives

$\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}$

$\mathbf{Maths\ not\ together = 2903040}$

<u>(c) The novels must be together and the chemistry books, together</u>

We have:

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the novels in:

$\mathbf{Novels = 3!\ ways}$

Next, arrange the chemistry books in:

$\mathbf{Chemistry = 5!\ ways}$

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

$\mathbf{n =Mathematics + 1 + 1}$

$\mathbf{n =2 + 1 + 1}$

$\mathbf{n =4}$

So, the number of arrangements is:

$\mathbf{Arrangements = n! \times 3! \times 5!}$

$\mathbf{Arrangements = 4! \times 3! \times 5!}$

$\mathbf{Arrangements = 17280}$

<u>(d) The mathematics must be together and the chemistry books, not together</u>

We have:

$\mathbf{Mathematics = 2}$

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the mathematics in:

$\mathbf{Mathematics = 2!}$

Literally, the number of chemistry and mathematics now is:

$\mathbf{n =Chemistry + 1}$

$\mathbf{n =5 + 1}$

$\mathbf{n =6}$

So, the number of arrangements of these books is:

$\mathbf{Arrangements = n! \times 2!}$

$\mathbf{Arrangements = 6! \times 2!}$

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

$\mathbf{Arrangements = ^7P_3}$

So, the total arrangement is:

$\mathbf{Total = 6! \times 2!\times ^7P_3}$

$\mathbf{Total = 6! \times 2!\times 210}$

$\mathbf{Total = 302400}$

Read more about permutations at:

brainly.com/question/1216161

8 0

2 years ago

A cuboid with a volume of 924cm^3 has dimensions 4cm, (x+1)cm and (x+11). Show clearly that x^2+12x-220=0 solve the equation by

garik1379 [7]

Answer:

$x^2+12x-220=0$ -- Proved

$x = 10\ \ \ x = -22$

Step-by-step explanation:

Given

$Volume = 924cm^3$

$Dimension: 4cm; (x+1)cm; (x+11)cm$

Required

Show that $x^2+12x-220=0$

The volume is calculated as:

$4 * (x + 1) * (x + 11) = 924$

Open the brackets

$(4x + 4) * (x + 11) = 924$

$4x^2 + 44x + 4x + 44 = 924$

$4x^2 + 48x+ 44 = 924$

Collect Like Terms

$4x^2 + 48x+ 44 - 924=0$

$4x^2 + 48x -880=0$

Divide through by 4

$\frac{4x^2}{4} + \frac{48x}{4} -\frac{880}{4}=0$

$x^2+12x-220=0$

Solving further:

Expand the expression

$x^2 + 22x - 10x - 220 = 0$

Factorize:

$x(x + 22) - 10(x + 22) = 0$

$(x - 10)(x + 22) = 0$

Split:

$x - 10 = 0;\ \ \ x + 22 = 0$

$x = 10\ \ \ x = -22$

5 0

2 years ago

HELPPPPPPP PLEASEEEEE

egoroff_w [7]

Answer:

5^15

Step-by-step explanation:

if they have the same base then you add the two top vaules therfore giving you c.

Brainliest plzzzzzzz

4 0

2 years ago