Answer:
Maximum walking speed of camel is 31.749V feet per second
Step-by-step explanation:
Walking speed of an animal is given by :
Speed = 5.7VI (in feet per second) where l is the animal's leg length.
For a camel, leg length is 5.7feet.
So maximum walking speed of camel will be:
Speed of camel = 5.7V * 5.7 = 5.7² V feet per second
Speed of camel = 31.749V feet per second
hence, maximum walking speed of camel is 31.749V feet per second
From the figure, we already have
RT = UT
and
TK = TK
Since these are already conditions for two sides being congruent, we only need an included angle to be congruent. So, the missing information is
∠RTK <span>≅ </span>∠<span>UTK</span><span />
Just add together these two fractions to determine by how much the height of the photo is shortened. 5/8 plus 3/8 comes to 8/8, or 1.
The photo is now 1 inch shorter than it was originally.
The equation y = x^2 has axis of symmetry of x = 0
The answer to the question is y = x^2 + 2 which is y = x^2 moved vertically up to 2 units
Answer:
b
Step-by-step explanation:
i dont know. i think rhis is my guess. just tell me the answer
