Question

What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (2, 5)?
y + 5 = x + 2
y − 2 = x − 5
y − 5 = −(x − 2)
y + 2 = −(x + 5)

Answer 1

Even though the slope isn't given, I was able to plug in the numbers into the formula and the answer is y-5=-(x-2)

Answer 2

We are given point (2,5).

We need to find the equation of line perpendicular to the given line and passes through the point (2, 5).

We know point-slope form :

y-y1 = m(x-x1).

Plugging values of (x1,y1) = (2,5) in above slope-intercept form, we get

y - 5 = m(x-2).

Which matches 3rd option y − 5 = −(x − 2).

So, the correct option is y − 5 = −(x − 2).