We are given point (2,5).
We need to find the equation of line perpendicular to the given line and passes through the point (2, 5).
We know point-slope form :
y-y1 = m(x-x1).
Plugging values of (x1,y1) = (2,5) in above slope-intercept form, we get
y - 5 = m(x-2).
Which matches 3rd option y − 5 = −(x − 2).
<h3>So, the correct option is y − 5 = −(x − 2).</h3>