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Vikki [24]
3 years ago
8

Is the following statement always, never, or sometimes true?

Mathematics
2 answers:
nlexa [21]3 years ago
7 0
We are given the following statement; A number raised to a negative exponent is negative. We can go through experimental points. In this case, when the number is positive, the result is also positive. If the number is negative, we can say the result is negative. 
pickupchik [31]3 years ago
3 0
Sometimes...

2^-3 = 1/(2^3) = 1/8

-2^-3 = 1/(-2^3) = -1/8
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Try using Symbolab!
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How do you simplify this?<br>x²y+xy² / y²+2/5 × xy​​​
polet [3.4K]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • How do you simplify this?
  • x²y+xy² / y²+2/5 × xy

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\sf\frac{  { x  }^{ 2  }  y+x { y  }^{ 2  }    }{  { y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy  } \\

Factor the expressions that are not already factored.

_____

<u>How </u><u>to</u><u> factorise</u><u> </u><u>:</u><u>-</u>

<u>NUMERATOR</u> \downarrow

\sf \: x ^ { 2 } y + x y ^ { 2 }

Factor out xy.

\sf \: xy\left(x+y\right)

<u>DENOMINATOR</u> \downarrow

\sf{ y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy \\

Factor out 1/5.

\sf \: {\frac{1}{5}y\left(2x+5y\right)}  \\

_____

Continuing...

\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)}  \\

Cancel out y in both the numerator and denominator.

\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)}  \\

Expand the expression.

\sf\frac{x^{2}+xy}{\frac{2}{5}x+y}  \\

This can further simplified to as \downarrow

=    \boxed{\boxed{\bf\frac{5x\left(x  +y\right)}{2x+5y}}}

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kolbaska11 [484]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

To make things less complicated, write down everything separate from the other. Then group together the intercepts and the coefficients into separate groups. After that, add them up separately in a format to where it will look like basic addition.

Hope this helps. I also apologize for any errors.

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