keeping in mind that when the logarithm base is omitted, the base 10 is assumed.
![\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \log(x)=2\implies \log_{10}(x)=2\implies 10^2=x\implies 100=x](https://tex.z-dn.net/?f=%5Ctextit%7Bexponential%20form%20of%20a%20logarithm%7D%20%5C%5C%5C%5C%20%5Clog_a%28b%29%3Dy%20%5Cqquad%20%5Cimplies%20%5Cqquad%20a%5Ey%3D%20b%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Clog%28x%29%3D2%5Cimplies%20%5Clog_%7B10%7D%28x%29%3D2%5Cimplies%2010%5E2%3Dx%5Cimplies%20100%3Dx)
Answer:
I think the answer for this question is C
Answer:
it's 6 cubic feet look you must count all the sides together also I took the test this cube has 6 sides so your answer will be 6 cubic feet ;)
Step-by-step explanation:
The answer is C
If the two chords intersect each other, that means that they must both be diameters. That means that JL + NL has to be equal to KL + ML. Because they are both diameters, they both have to be equal to each other. The only choice that satisfies this condition is C where both of the diameters are 16 in long.
Hope this helps :)
First pool: 21 liters per min so to get 3100 gone do 3100 divided by 21 which equals 147
Second pool: 33 liters per min and you have 3472 divided 33 = 105