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2 years ago

Please help me I need this for tonight

Mathematics

1 answer:

Dimas [21]2 years ago

7 0

C
because if you substitute 4 into x you do 4+8 thats 12
3(4) = 12
so therefore its C

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Perpendicular to y=4x-7; contains the point (4,3)

san4es73 [151]

Okay, so a general rule for finding perpendicular lines in the form of y = mx + b is y = (-1/m) + b.
First, let's ignore b (-7) because we're going to find that later.
A perpendicular line to y = 4x + b is y = -1/4x + b.
Alright, so now let's plug in the values. They are in the form of (x,y), so let's plug them in accordingly.

3 = -1/4(4) + b
3 = -1 + b
b = 4
y = -1/4x + 4
So a line perpendicular to y = 4x - 7 is y = -1/4x + 4.

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2 years ago

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Aleonysh [2.5K]

Answer:

whats the question

Step-by-step explanation:

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2 years ago

Ricky race $640 in a charity walk last year this year he raised 15% more than he raised last year how much money did Ricky raise

Mashutka [201]

He raised $736.

One way is to multiply 640 x .15 = 96
Add 96 + 640 = 736

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2 years ago

Simplify the expression 3(6-2x)

ehidna [41]

Answer:

-3

Step-by-step explanation:

3 times 6 is 18

3 times -2x is -6x

put -6x on the other side and divide 18 by -6x and you get -3

4 0

2 years ago

Find the annual rate of interest. Principal = 4600 rupees, Period = 5 years, Total amount = 6440 rupees, Annual rate of interest

Len [333]

The annual rate of interest per year is 8%

<u>Solution:</u>

Given:- Principal (p) = 4600 rupees, Time –Period (t) = 5 years, Total amount(A) = 6440 rupees

First we will calculate the Interest and then using formula of simple interest we will calculate the rate of interest

Interest = Amount – Principal

Interest = 6440 – 4600 = 1840

Now using the formula of simple Interest and on putting values we get,

$\text {Simple Interest }=\frac{P \times R \times T}{100}$

Where "P" is the principal and "R" is the rate of interest per annum and "T" is the time period

$1840=\frac{4600 \times R \times 5}{100}$

$\begin{aligned} \mathrm{R} &=\frac{1840 \times 100}{4600 \times 5} \\\\ \mathrm{R} &=\frac{1840}{230} \\\\ \mathrm{R} &=8 \% \end{aligned}$

Hence, the required rate of interest per year is 8%

6 0

3 years ago