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scoundrel [369]
2 years ago
14

How do I solve question 6a?

Mathematics
1 answer:
Sholpan [36]2 years ago
3 0

Answer:

bbbbbbbbbbbbbbbbbbbbbbbbb

Step-by-step explanation:

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Please help ASAP!!! Thank you!!
Eddi Din [679]

Answer:

- 3/x-1

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
A company makes poppy lapel pins.
mezya [45]

Answer:

<h2>The required percentage is 65.45%.</h2>

Step-by-step explanation:

The total costing is 1000 \times 1.10 = 1100

35% were given to the charity, hence 350 were given to the charity.

There are (1000 - 350) = 650 lapel pins remaining.

60% of 650 = \frac{60}{100} \times 650 = 390 werre sold for 3.00 each. Hence, earning from here is 390 \times3 = 1170.

40% of 650 = 260 were sold at 5.00 for 2. It can also be said that \frac{260}{2} = 130 were sold at 5.00 each. Earning from this section is 130 \times5 = 650

Total earning is (1170 + 650) = 1820.

Profit percentage = \frac{1820 - 1100}{1100} \times100 = \frac{720}{11} = 65.45

5 0
3 years ago
Find the unit rate!!!<br><br> WILL GIVW BRAINLIEST!!!!
Whitepunk [10]

Answer:

10 to 2

Step-by-step explanation:

Please give the B

I would appreciate it :)

7 0
2 years ago
[HELP ASAP 50 POINTS] 17, 18, 19, 20
Charra [1.4K]

17) f(x) = 16/(13-x).

In order to find domain, we need to set denominator expression equal to 0 and solve for x.

And that would be excluded value of domain.

13-x =0

Adding x on both sides, we get

13-x +x = x.

13=x.

Therefore, domain is All real numbers except 13.



18).f(x) = (x-4)(x+9)/(x^2-1).

In order to find the vertical asymptote, set denominator equal to 0 and solve for x.

x^2 -1 = 0

x^2 -1^2 = 0.

Factoring out

(x-1)(x+1) =0.

x-1=0 and x+1 =0.

x=1 and x=-1.

Therefore, Vertical asymptote would be

x=1 and x=-1

19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)

We have degrees of numberator and denominator are same.

Therefore, Horizontal asymptote is the fraction of leading coefficents.

That is 7/2.


20) f(x)=(x^2+3x-2)/(x-2).

The degree of numerator is 2 and degree of denominator is 1.

2>1.

Degree of numerator >  degree of denominator .

Therefore, there would no any Horizontal asymptote.

6 0
3 years ago
For number 28, are the 2 graphs parallel, perpendicular or neither?
d1i1m1o1n [39]
The lines are parallel
5 0
3 years ago
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