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nevsk [136]
3 years ago
6

What is the output, or y-value, when you input x = 2 into the function: y = 2x3 − 6x.

Mathematics
2 answers:
valentinak56 [21]3 years ago
8 0
2(2)3-6(2)
4(3)- 12
12-12 =0 =y


now if the 2x3 was actually referring to 2(3) then it will be:
2(3)-6(2)
6-12 =-6=y


I hope this helps.
ahrayia [7]3 years ago
5 0
First, put fill in the X's with 2.
y = 2*2*3 - 6*2

Next, multiply.
y = 12 - 12

Finally, subtract!
y = 0

Apparently, Y equals 0.
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Find the orthogonal complement W⊥ of W and give a basis for W⊥. W = x y z : x = 1 2 t, y = − 1 2 t, z = 6t.
igor_vitrenko [27]

Answer:

W⊥= (a, b, c)

a = v - (1/2)w

b = v

c = w

Basis for W⊥ = <(1,1,0),(-1/2,0,1)>

Step-by-step explanation:

The orthogonal complement of W is the set of vectors (a,b,c) that satisfy:

(x,y,z)·(a,b,c) = 0

ax + by + cz = 0

So, taking into account that x=12t, y=-12t and z=6t, the equation above is equal to:

12ta + -12tb + 6tc = 0

12a - 12b + 6c = 0

Then, if we made b=v and c=w and solve for a, we get:

12a - 12v + 6w = 0

a = (12v - 6w)/12

a = v - (1/2)w

Therefore, the orthogonal complement W⊥ of W has the form:

W⊥ = (a,b,c) = (v - (1/2)w, v, w)

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W⊥ = (v - (1/2)w, v, w)

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W⊥ = v(1,1,0) + w(-1/2,0,1)

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