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Anestetic [448]
2 years ago
14

What are the two solutions to this problem? -3/2 +3/2 -1/5 +1/5

Mathematics
1 answer:
jarptica [38.1K]2 years ago
4 0
10x^2 - 3 = -13x      ( because they are both log4 of)

10x^2 + 13x - 3 = 0

(5x - 1)( 2x + 3) = 0  

x = 0.2   or     -1.5
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2 years ago
16 POINTS HELP ASAP plzzzzzzzzz
schepotkina [342]

Answer:

                            \large\boxed{\large\boxed{\sqrt{3}

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You are comparing irrational numbers.

By inspection, i.e. at first sight you can only compare \sqrt{3} \text{ }and\text{ } 2\sqrt{3} because they have the same radicand.

You can order: \sqrt{3}

You can introduce the 2 inside the radical by squaring it:

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Since 5 is between 3 and 12, you can order:

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5 is less than 9 and the square root of 9 is 3; hence, \sqrt{5} and \sqrt{5}

Now you must determine whether π is less than or greater than \sqrt{12}

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