<span>The quadrilateral ABCD have vertices at points A(-6,4), B(-6,6), C(-2,6) and D(-4,4).
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<span>Translating 10 units down you get points A''(-6,-6), B''(-6,-4), C''(-2,-4) and D''(-4,-6).
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Translaitng <span>8 units to the right you get points A'(2,-6), B'(2,-4), C'(6,-4) and D'(4,-6) that are exactly vertices of quadrilateral A'B'C'D'.
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</span><span>Answer: correct choice is B.
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They give the formula as:
Surface Area =<span> (2 • <span>π <span>• r²) + (2 • <span>π • r • height)</span></span></span></span>
However the 2*PI*r^2 part of the formula is used to calculate the 2 "ends" of a cylinder. Since the problem states that you are NOT to count any of surface area of the "ends" then you only need the <span>(2 • <span>π • r • height) part of the formula.
So, r = 3 inches and height = 8 * 3 inches, the side area equals
2 * PI * r * height
2 * 3.14159 * 3 * 24 =
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452.39 cubic inches which is the lateral area.</span></span></span>
Answer: 5,4
Step-by-step explanation:
I did the test
