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3 years ago

Factor the polynomial below 20x^2-45

Mathematics

2 answers:

stiks02 [169]3 years ago

8 0

$20x^2-45=5(4x^2-9)=5[(2x)^2-3^2]=5(2x-3)(2x+3)\\\\--------------------------\\\\use:a^2-b^2=(a-b)(a+b)$

rodikova [14]3 years ago

3 0

$(a+b)(a-b)=a^2-b^2\\---------------------\\\\20x^2-45=5\cdot4x^2-5\cdot9=5\cdot(4x^2-9)=\\\\.\ \ \ \ \ \ \ \ \ \ \ \ =5\cdot[(2x)^2-3^2]=5\cdot(2x+3)(2x-3)$

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Read 2 more answers

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